<span>13-((4/5)+(6/8))
Make your fractions have common denominators
</span>13-((32/40)+(30/40))
Add your fractions and simplify
13-(62/40)
or
13-(31/20)
or
13-(1 11/20)
Then turn 13 into a fraction with a common denominator! Im going to use the second fraction method (31/20)
13 written as a fraction is 13/1, its LCD with 31/20 is 20. I now multiply the top and bottom by 20
260/20
Now I rewrite the problem again
(260/20)-(31/20)
Which equals
229/20!
This is your unsimplified answer
Finally you simplify and get
11 9/20
Answer:
.5 and .5, .75 and .25, ect
Answer:
Step-by-step explanation:
Hey, do you mean what is the final charge? If so, then look at my next steps
If you mean the final charge then first multiply 10% by 360 , basically 10/100 multiplied by $360 which is equals to $36. Since it is interest, add $36 to $360. The answer will be $396. Then you add on the $19 which would bring the total to $415.
Hehe I am no expert but this is what I did . Tried my best
Answer:
The value of the experimental probability is greater
Step-by-step explanation:
For the theoretical probability;
the probability that a card with the number 3 is selected is 1/5
We consider that the probabilities of each selection are equal, for the theoretical probability
For the experimental, we simply place the frequency of the selection 3 over the total
that will be 128/400 = 8/25
As we know that 8/25 is greater than 1/5
We can conclude that the value of the experimental probability is greater than that of the theoretical
Answer:
<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>
Step-by-step explanation:
We know
for any real value of <em>a</em>.
|a| = b > 0 - <em>two solutions: </em>a = b or a = -b
|a| = 0 - <em>one solution: a = 0</em>
|a| = b < 0 - <em>no solution</em>
<em />
|x + 6| - 4 = c
for c = 5:
|x + 6| - 4 = 5 <em>add 4 to both sides</em>
|x + 6| = 9 > 0 <em>TWO SOLUTIONS</em>
for c = -10
|x + 6| - 4 = -10 <em>add 4 to both sides</em>
|x + 6| = -6 < 0 <em>NO SOLUTIONS</em>
<em></em>
Calculate the solutions for c = 5:
|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9 <em>subtract 6 from both sides</em>
x = 3 or x = -15
