How many digits you need to write all 3 digit numbers

Mathematics

1 answer:

7nadin3 [17]2 years ago

8 0

Answer: 720

Step-by-step explanation: if what you want are all possible three digit numbers with no repetition of the digits then you have 10 choices for the first digit, you have 9 choices for the 2nd digit, and you have 8 choices for the 3rd digit giving you 10x9x8 = 720 in all.

You might be interested in

4+2(6+15)<br><br> HELP PLSSSSSS

Airida [17]

Answer:

Step-by-step explanation:

Multiply the two by both numbers inside the parenthesis

2 x 6 = 12 2 x 15 =30

Add those numbers together

12 + 30 = 42

Then add the remaining four to that number

4 + 42

7 0

2 years ago

3 / m + 4 - 4 / m = 6 (i) Show that this equation can be written as 6m^2 + 25m+16= 0

Evgen [1.6K]

Answer:

Proved Below

Step-by-step explanation:

$\sf \frac{3}{m+4} - \frac{4}{m} = 6\\LCM = m(m+4)\\Multiplying \ both \ sides \ by\ m(m+4)\\3m - 4(m+4) = 6m(m+4)\\3m-4m-16 = 6m^2+24m\\-m-16 = 6m^2+24m\\Adding\ m\ to\ both\ sides\\-16 = 6m^2+24m+m\\-16 = 6m^2+25m\\Adding \ 16 \ to \ both \ sides\\0 = 6m^2+25m+16\\OR\\6m^2+25m+16 = 0$