![\sf\dfrac{x}{100}+\dfrac{3}{100}=\dfrac{8}{100}](https://tex.z-dn.net/?f=%5Csf%5Cdfrac%7Bx%7D%7B100%7D%2B%5Cdfrac%7B3%7D%7B100%7D%3D%5Cdfrac%7B8%7D%7B100%7D)
Subtract 3/100 to both sides:
![\sf\dfrac{x}{100}=\dfrac{5}{100}](https://tex.z-dn.net/?f=%5Csf%5Cdfrac%7Bx%7D%7B100%7D%3D%5Cdfrac%7B5%7D%7B100%7D)
Cross multiply:
![\sf100x=500](https://tex.z-dn.net/?f=%5Csf100x%3D500)
Divide 100 to both sides:
![\sf~x=5](https://tex.z-dn.net/?f=%5Csf~x%3D5)
Or we could just multiply both sides of the equation by 100, to give us:
![\sf~x+3=8](https://tex.z-dn.net/?f=%5Csf~x%2B3%3D8)
Subtract 3 to both sides:
9/200. divide 45 and 1000 both by 5 to reduce it.
Answer:
![y = -\frac{4}{3}x + 4](https://tex.z-dn.net/?f=%20y%20%3D%20-%5Cfrac%7B4%7D%7B3%7Dx%20%2B%204%20)
Step-by-step explanation:
Use the slope-intercept form to write the equation if the line of the graph given.
, where,
b = y-intercept, which is where the line cuts across the y-axis = 4.
m = slope = ![\frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 4}{3 - 0} = \frac{-4}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7By_2%20-%20y_1%7D%7Bx_2%20-%20x_1%7D%20%3D%20%5Cfrac%7B0%20-%204%7D%7B3%20-%200%7D%20%3D%20%5Cfrac%7B-4%7D%7B3%7D%20)
Substitute m = ⁴/3 and b = 4, into the slope-intercept formula to get the equation of the line:
![y = mx + b](https://tex.z-dn.net/?f=%20y%20%3D%20mx%20%2B%20b%20)
![y = -\frac{4}{3}x + 4](https://tex.z-dn.net/?f=%20y%20%3D%20-%5Cfrac%7B4%7D%7B3%7Dx%20%2B%204%20)
4
x
+
y
−
2
z
=
0
4
x
+
y
-
2
z
=
0
,
2
x
−
3
y
+
3
z
=
9
2
x
-
3
y
+
3
z
=
9
,
−
6
x
−
2
y
+
z
=
0
-
6
x
-
2
y
+
z
=
0
x
+
2
y
=
4
x
+
2
y
=
4
,
2
x
+
4
y
=
8
2
x
+
4
y
=
8
3
x
+
y
=
4
3
x
+
y
=
4
,
6
x
−
7
y
=
2
Graph K. This is because the cost of a gallon of milk is not increasing constantly, as in a linear rate, but it has only increased a few times in a year. Therefore, graph K shows that a gallon of milk is a steady, unchanged price, then the cost rises and stays the same, then rises again and stays the same. So, it is not a linear graph because the cost of the milk is not going up at a constant rate.