In box 1, the reason that justifies the statement, m∠BAD = m∠BAC + m∠CAD, is: angle addition postulate.
<h3>What is the Angle Addition Postulate?</h3>
The angle addition postulate states that the measure of a larger angle equals the sum of smaller angles that make up the larger angle.
∠BAD comprises of ∠BAC and ∠CAD.
Therefore, based on the angle addition postulate, m∠BAD = m∠BAC + m∠CAD.
The missing reason in box 1 would be: angle addition postulate.
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Answer:
multiply 5 times 12 then divide by 2 which equals 30 then 15 times 36 divided by 2
Answer:
m∠EGF = 65° and m∠CGF = 115°
Step-by-step explanation:
Given;
∠EFG = 50°
EF = FG
Solution,
In ΔEFG m∠EFG = 50° and EF = FG.
Since triangle is an isosceles triangle hence their base angles are always equal.
∴
Let the measure of ∠EGF be x.
∴ 
Now by angle Sum property which states "The sum of all the angles of a triangle is 180°."
m∠EFG + m∠FEG + ∠EGF = 180
Hence
m∠EGF = 65°
Also 'The sum of angles that are formed on a straight line is equal to 180°."
m∠EGF + m∠CGF = 180°
65° + m∠CGF = 180°
m∠CGF = 180° - 65° = 115°
Hence m∠EGF = 65° m∠CGF = 115°
Answer:
i found this so srry if its wrong i saw no one answering this so i wanna help
Step-by-step explanation:
so, x*(7/100) + (3500 - x)*(4/100) = 197
=> 3x + 14000 = 19700
=> 3x = 19700 - 14000
=> x = 5700/3 = 1900
Step-by-step explanation:
2•4 =8
8/3 =2 2/3
answer : 3
