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olga nikolaevna [1]

3 years ago

8

7 minutes left and im dead and im only at the 4th question, help?

2 answers:

sattari [20]3 years ago

6 0

Answer:

angle T = angle D

Tomtit [17]3 years ago

4 0

Answer:

taking back my points

Step-by-step explanation:

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The amount of time all students in a very large undergraduate statistics course take to complete an examination is distributed c

Anestetic [448]

Answer:

a) The mean is $\mu = 60$

b) The standard deviation is $\sigma = 9$

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The probability a student selected at random takes at least 55.50 minutes to complete the examination equals 0.6915.

This means that when X = 55.5, Z has a pvalue of 1 - 0.6915 = 0.3085. This means that when $X = 55.5, Z = -0.5$

So

$Z = \frac{X - \mu}{\sigma}$

$-0.5 = \frac{55.5 - \mu}{\sigma}$

$-0.5\sigma = 55.5 - \mu$

$\mu = 55.5 + 0.5\sigma$

The probability a student selected at random takes no more than 71.52 minutes to complete the examination equals 0.8997.

This means that when X = 71.52, Z has a pvalue of 0.8997. This means that when $X = 71.52, Z = 1.28$

So

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{71.52 - \mu}{\sigma}$

$1.28\sigma = 71.52 - \mu$

$\mu = 71.52 - 1.28\sigma$

Since we also have that $\mu = 55.5 + 0.5\sigma$

$55.5 + 0.5\sigma = 71.52 - 1.28\sigma$

$1.78\sigma = 71.52 - 55.5$

$\sigma = \frac{(71.52 - 55.5)}{1.78}$

$\sigma = 9$

$\mu = 55.5 + 0.5\sigma = 55.5 + 0.5*9 = 55.5 + 4.5 = 60$

Question

The mean is $\mu = 60$

The standard deviation is $\sigma = 9$

6 0

2 years ago

Kendrick received 24 fewer e-mails than he did on Thursday. If he received a total of 126 e-mails on those two days, how many di

telo118 [61]

E+(e-24)=126

2e-24=126

2e=150

e=75

So (s)he recieved 75 and 75-24=51 emails on those days.

3 0

3 years ago

(5x ² +1) (2x + 3) - 2 x (5²-3)

kotegsom [21]

Answer:

y = 3 suh slid este ob cine este a, b și g au nevoie de acel kinfo pentru a termina

Step-by-step explanation:

6 0

3 years ago

Solve the equation for the variable.<br><br><img src="https://tex.z-dn.net/?f=%20-%205v%20%2B%209%20%3D%20%20-%20v%20%2B%2017" i

AlekseyPX

Answer:

v= - 2

Step-by-step explanation:

...............

8 0

3 years ago

PLEASE HELP with3,4,5,6 <br> DUE IN 20 min

Alika [10]

Answer:

3.

$volume \ of \ cone = \frac{1}{3}\pi r^2h = \frac{1}{3}*3.14*6*6*15 = 3.14*36*5 = 565.2cm^3$

4.

$volume \ of \ cone = \frac{1}{3}\pi r^2 h = \frac{1}{3} *3.14* 12*12*20 = 3.14*12*4*20 = 3014.4cm^3$

5.

$volume \ of \ sphere = \frac{4}{3} \pi r^3 = \frac{4}{3}*3.14 * 3*3*3* = 4*3.14*9 = 113.0cm^3$

6.

$diameter = 13cm\\\\radius = 6.5cm\\\\volume \ of \ sphere = \frac{4}{3} \pi r^3= \frac{4}{3} *3.14*6.5*6.5*6.5 = 1149.8cm^3$

6 0

3 years ago