1. 0 - 34 + 13 - 5 = -26.....26 ft below the surface
2. y = 15x + 50
220 = 15x + 50
220 - 50 = 15x
170 = 15x
170/15 = x
11 1/3 = x......he worked 11 1/3 hrs.......not sure about this...because it does not specify how many visits he made...but if this was just for 1 visit, then he worked 11 1/3 hrs
The vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.
Given an equation showing profits of A Christmas vendor as
P=-0.1
+30g-1200.
We have to find the number of gingerbread houses that the vendor needs to sell in order to earn profit of $665.60 and $1500.
To find the number of gingerbread houses we have to put P=665.60 in the equation given which shows the profit earned by vendor.
665.60=-0.1
+30g-1200
0.1
-30g+1200+665.60=0
0.1
-30g+1865.60=0
Divide the above equation by 0.1.
-300g+18656=0
Solving for g we get,
g=[300±
]/2*1
g=[300±![\sqrt{90000-74624}]/2](https://tex.z-dn.net/?f=%5Csqrt%7B90000-74624%7D%5D%2F2)
g=[300±
]/2
g=(300±124)/2
g=(300+124)/2 , g=(300-124)/2
g=424/2, g=176/2
g=212,88
Because 212 is much greater than 88 so vendor prefers to choose selling of 88 gingerbread houses.
Put the value of P=1500 in equation P=-0.1
+30g-1200.
-0.1
+30g-1200=1500
0.1
-30g+1500+1200=0
0.1
-30g+2700=0
Dividing equation by 0.1.
-300g+27000=0
Solving the equation for finding value of g.
g=[300±
]/2*1
=[300±![\sqrt{90000-108000}] /2](https://tex.z-dn.net/?f=%5Csqrt%7B90000-108000%7D%5D%20%2F2)
=[300±
]/2
Because
comes out with an imaginary number so it cannot be solved for the number of gingerbread houses.
Hence the vendor has to sell 88 gingerbread houses to earn a profit of $665.60 and there is no chance that the vendor will earn $1500.
Learn more about equation at brainly.com/question/2972832
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Answer: Options 'C' and 'E' are correct.
Step-by-step explanation:
Since we have given that
Quantity of snowfall in February at Delphine's house be f centimeters
Quantity of snowfall in March at Delphine's house be 40% more than in February.
According to question,

So, Options 'C' and 'E' are correct.
i.e. C) 1.4f
E) 