Answer:
compare the distance between the lines at one point to the distance between the lines at another point
Step-by-step explanation:
You can construct perpendiculars at different points and compare the distance between the lines at those perpendiculars. The distance between parallel lines is the same everywhere.
<span>y=x-4
y=-x+6
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Substitute x - 4 for y in </span>y=-x+6
x-4=-x+6<span>
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Add X on each side
</span><span>x-4+x</span>=-<span>x+6+x
</span>2x - 4 = 6
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Add 4 on each side
<span>2x-4+4</span>=<span>6+4
</span>2x = 10
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Divide by 2 on each side
2x ÷ 2 = 10 ÷ 2
x = 5
Now we have X
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To find Y we substitute 5 for x in y=<span>x-<span>4
</span></span>y = 5 - 4
y = 1
-----------------------------------------------------
Your answers are Y = 1 and X = 5
THE ANSWER
let be S1 = <span>Serravalle
S2= </span><span>San Marino and
S3= </span><span>Chiesanuova
for finding the distance </span><span>Chiesanuova from Serravalle,
(distance S1 to S2) + (distance S2 to S3) = </span><span>982 miles + 833 miles =1.815 miles
the answer is </span>B. 1, 815 miles
Hi there! :)
A radical equation is an equation in which a variable (ex. x, y, a, v) is under a radical sign. The only equation that has a variable under a radical (x) is the second option. There is an x next to the 2 under the radical.
I hope this helps, DM me if you have anymore questions. :)
~kaikers
