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gavmur [86]
3 years ago
15

1. Find the degree of the monomial 6p3q2.

Mathematics
1 answer:
frozen [14]3 years ago
7 0
1. degree of monomial...add the exponents...degree of 5
2. 7t^2 + 9 + 6t^2 + 8 = 13t^2 + 17
3. 3n(4n^2 + 5n) = 12n^3 + 15n^2
4. 18s - 63 = 9(2s - 7)
5. ?? simpler form of what ?
6. (x + 7)(x + 5) = x^2 + 5x + 7x + 35 = x^2 + 12x + 35
7. (2z - 3)(2z - 3) = 4z^2 - 6z - 6z + 9 = 4z^2 - 12z + 9
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Drag each tile to the correct box consider the given functions f,g and h place the tiles in order from least to greatest accordi
Alja [10]

Answer:

Step-by-step explanation:

By definition, the average rate of change of a function f over an interval [a,b] is given by

\dfrac{f(b)-f(a)}{b-a}

compute the quantity

\dfrac{f(3)-f(0)}{3}

for all the three function

Average rate of change of f:

We will simply use the table to check the values for f(3) and f(0):

\dfrac{f(3)-f(0)}{3}=\dfrac{10-1}{3} = 3

Average rate of change of g:

We will use the graph to to check the values for g(3) and g(0):

\dfrac{g(3)-g(0)}{3}=\dfrac{8-1}{3} = \dfrac{7}{3}

Average rate of change of h:

We can plug the values in the equation to get h(3) and h(0):

h(3)=3^2+3-6=9+3-6=6,\quad h(0)=0^2+0-6=-6

And so the average rate of change is

\dfrac{h(3)-h(0)}{3}=\dfrac{6-(-6)}{3} = 4

3 0
3 years ago
Roenfeld Corp believes the following probability distribution exists for its stock. What is the coefficient of variation on the
jok3333 [9.3K]

Complete question is attached;

Answer:

Option D: 0.3069

Step-by-step explanation:

Formula for coefficient of variation on the company's stock is;

CV = σ/E(r)

Where σ is the standard deviation and E(r) is expected value of return.

From the attached image, we can find E(r) as;

E(r) = 0.45(25) + 0.5(15) + 0.05(5)

E(r) = 19%

From online calculation, the standard deviation is 5.83%

Thus;

CV = 5.831/19

CV ≈ 0.3069

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Total 60 vaccinations that consisted of 184 doses.
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Find the circumference for the following circle. use 22/7 for pi.
kondor19780726 [428]

Answer:

D.16.5m

because circumference=21/7×5.25

=16.5m

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A car drives 195 miles in 3 hours and 15 minutes. what is the average speed of the car?
g100num [7]
1 mpm or 0.0166666666 repeating mph
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