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jasenka [17]
3 years ago
12

If the oven is used for two hours to bake cookies how many kilowatt hours are used

Physics
1 answer:
LUCKY_DIMON [66]3 years ago
3 0
. In 1 hour 2400 kilowatts are used. In 2 hours a total of 4800 kilowatts are used.
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g According to the Third Law, the action and reaction forces are exactly equal in magnitude and in opposite directions. So when
torisob [31]

Answer:

One way to look at this is to consider the forces acting on any point in a string.

For a very small portion of string F = M a must still hold. As M approaches zero the small portion of string would have to approach infinite acceleration if the net force on that portion of string were not zero.

One generally considers the net force acting on the center of mass of an object not  the individual forces acting on each infinitesimal mass composing

the object.

7 0
3 years ago
Using the following equation, find in seconds 145m = 9 m/s x t-35m
Zina [86]

Answer:

t = 20 s

Explanation:

145 m = 9 m/s × t – 35m

We can obtain the value of t in seconds by doing the following:

145 m = 9 m/s × t – 35m

Add 35 m to both side as shown below:

145 m + 35 m = 9 m/s × t – 35m + 35 m

180 m = 9 m/s × t

Divide both side by 9 m/s

t = 180 m / 9 m/s

t = 20 s

Therefore, the value of t is 20 seconds.

5 0
3 years ago
a car dealer sells 4 makes of cars in 5 colors with either standard or automatic transmissions. how many variations does the dea
Anuta_ua [19.1K]

<u>The number of variations the dealership have is 40 cars</u>.

Data given;

  • The number of different product = 4
  • The number of transmission = 2 (standard or automatic)
  • The numbers of colors available = 5

<h3>Dealership variation </h3>

This is the total numbers of cars available in the dealer shop at the moment.

To get that, we simply multiply the numbers of colors available, the number of transmission and the makes of car available.

This is equal to

4*2*5=40

From the above calculation, we can say that <u>the variations the dealership offers is 40</u>

<u />

Learn more on combination here

brainly.com/question/10339517

7 0
3 years ago
If I measure the current to be 0.5 A and the voltage is 4.5 V. What is my Power?
Korvikt [17]
As we know that P=IV so P = (0.5A)(4.5V)
                                            P= 2.25 watt
6 0
3 years ago
A 1.40-kg block is on a frictionless, 30 ∘ inclined plane. The block is attached to a spring (k = 40.0 N/m ) that is fixed to a
Oliga [24]

Answer:

the mass drop by 6.5cm before coming to rest.

Explanation:

Given that:

the mass of the block M= 1.40 kg

angle of inclination θ = 30°

spring constant K = 40.0 N/m

mass of the suspended block m = 60.0 g = 0.06 kg

initial downward speed = 1.40 m/s

The objective is to determine how far does it drop before coming to rest?

Let assume it drops at y from a certain point in the vertical direction;

Then :

Workdone by gravity on the mass of the block is:

w_1g = 1.4*9.81*y*sin30 = - 6.867y

Workdone by gravity on the mass of the suspended block is:

w_2g = 0.06*9.81 = 0.5886

The workdone by the spring = -1/2ky²

= -0.5 × 40y²

= -20 y²

The net workdone is = -20 y² - 6.867y + 0.5886y

According to the work energy theorem

Net work done = Δ K.E

-20 y² - 6.867y + 0.5886 = 1/2 × 0.06 × 1.4²

-20 y²  - 6.867y + 0.5886 = 0.5 × 0.1176

-20 y²  - 6.867y + 0.5886 = 0.0588

-20 y²  - 6.867y + 0.5886 - 0.0588

-20 y²  - 6.867y + 0.5298 = 0

multiplying through by (-)

20 y²  + 6.867y - 0.5298 = 0

Using the quadratic formula:

\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}

where;

a = 20 ; b = 6.867 c= - 0.5298

\dfrac{-(6.867)  \pm \sqrt{(6.867)^2-(4*20*-0.5298)}}{2*(20)}

= \dfrac{-(6.867)  + \sqrt{(6.867)^2-(4*20*-0.5298)}}{2*(20)} \ \ \ OR \ \ \  \dfrac{-(6.867)  - \sqrt{(6.867)^2-(4*20*-0.5298)}}{2*(20)}= 0.0649 OR  −0.408

We go by the positive integer

y = 0.0649 m

y = 6.5 cm

Therefore; the mass drop by 6.5cm before coming to rest.

7 0
4 years ago
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