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sergiy2304 [10]
3 years ago
6

Simplify 1/2 (8x-4) +7x

Mathematics
1 answer:
devlian [24]3 years ago
8 0

Answer:

C. 11x -2

Step-by-step explanation:

Distribute the 1/2 to 8x-4 which simplifies to 4x -2. Add that to 7x and the expression becomes 11x-2.

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How many words of five letters can be created that start with the letter T, contain 2 other consonats and end with 2 vowels? Not
Jet001 [13]

If we're only counting 5 vowels (A, E, I, O, U) and 20 consonants (everything else, minus T), then there are

\dbinom52=\dfrac{5!}{2!(5-2)!}=10

ways of picking the vowels, and

\dbinom{20}2=\dfrac{20!}{2!(20-2)!}=190

ways of picking the consonants.

We want the word to start with T, and we'll allow any arrangement of the other 4 letters, so that the total number of words is

4!\dbinom52\dbinom{20}2=\boxed{45,600}

Keep in mind that this means words like TRIES and TIRES are treated as different.

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3 years ago
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Last month, Katie started training for the swim team. She swam 20 laps every day for 18 training days. This month, Katie wants t
nasty-shy [4]

She swim 20 laps every day for 18 training days

so total laps done last month = 20*18 = 360 laps

She will swim 3 more laps per training day and add more training days to her monthly schedule.

20 laps + 3 laps = 23 laps

(a)If Katie adds 5 training days to her schedule this month, will she swim 215 more laps?

18 days + 5 days more = 23 days

23 laps every day for 23 training days

so total laps = 23*23 = 529 laps. That is 169 more laps than 360 laps done last month. Hence she cannot swim 215 more laps

If Katie adds 10 more training days to her schedule this month, will she swim 215 more laps?

18 days + 10 days more = 28 days

23 laps every day for 28 training days

so total laps = 23*28 =644 laps. That is 284 more laps than 360 laps done last month. Hence she can swim 215 more laps

(c)If Katie adds 6 more training days to her schedule this month, will she swim 215 more laps?

18 days + 6 days more = 24 days

23 laps every day for 24 training days

so total laps = 23*24 =552 laps. That is 192 more laps than 360 laps done last month. Hence she cannot swim 215 more laps

Build an equation for finding the number of additional training days she needs to swim 215 more laps

Let x be the number of days more

So training days = 18 + x

215 more laps , so total laps = 360 + 215 = 575

3 more laps per training day so 20 + 3 = 23 laps per day

laps * training days = total laps

so equation becomes

23 * (18+x) = 575

Now solve for x

414 + 23x = 575

Subtract 414 from both sides

23x = 161

x= 7

so she needs 7 training days to swim 215 more laps

3 0
3 years ago
A new shopping mall records 120 total shoppers on their first day of business. Each day after that, the number of shoppers is 10
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Plz Answer 10 points
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I'll say the first one and the second last one, because the other ones don't make sense to me...

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