Distance === 3hrs * 15miles / 1hr === 45 miles.
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The solution of cos θ = −0.3 is θ = 107.45760312 degrees
<em><u>Solution:</u></em>
Given that we have to find the primary solution of 
To solve this equation, you must find the unknown (theta)

Use the inverse of cosine (Arccos) to find the angle measurement (in degrees) of theta

We know that arccos (-0.3) = 107.45760312 degrees
[ If you reference a unit circle or use a calculator ]

Therefore solution of cos θ = −0.3 is θ = 107.45760312 degrees
Answer:
the equation of the hyperbola is y^2/12-x^2/4=1
Step-by-step explanation:
Answer:
-28
Step-by-step explanation:
Answer:
The probability that the sample proportion will be greater than 13% is 0.99693.
Step-by-step explanation:
We are given that a large shipment of laser printers contained 18% defectives. A sample of size 340 is selected.
Let
= <u><em>the sample proportion of defectives</em></u>.
The z-score probability distribution for the sample proportion is given by;
Z =
~ N(0,1)
where, p = population proportion of defective laser printers = 18%
n = sample size = 340
Now, the probability that the sample proportion will be greater than 13% is given by = P(
> 0.13)
P(
> 0.13) = P(
>
) = P(Z > -2.74) = P(Z < 2.74)
= <u>0.99693</u>
The above probability is calculated by looking at the value of x = 2.74 in the table which has an area of 0.99693.