In both the figures we have a Right Angled Triangle.
Two sides of the right angled triangles are given and we are to find the Third side. This can be done using the Pythagoras Theorem, which states:
Hypotenuse² = Base² + Perpendicular²
For 1st figure, we have
Base = 21
Perpendicular = 20
So,
Hypotenuse² = 20² + 21² = 841
⇒
Hypotenuse = 29 (1st option is correct)
For 2nd Image, we have
Base= 6
Hypotenuse = 10
So, we can write:
10² = 6² + Perpendicular²
Perpendicular² = 64
⇒
Perpendicular = 8 (Option Fourth)
You know the numbers must be consecutive (which means right next to each other) so it can't be the first one. Therefore 21 and 23 is the least possible pair of integers.
3 + 5x = 20 + 7x
First subtract 20 to both sides
-17 + 5x = 7x
Next subtract 5x to both sides (we are trying to get x all in one side)
-17 = 2x
Divide 2 to isolate the x
-17/2 = x or -8.5 = x
Answer:
im too late
Step-by-step explanation:
