Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean and standard deviation is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:
Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:
Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
#SPJ1
Compare the two sets of numbers with a ratio. 1 can for 24 servings is to 1/2 can for x servings.
x= # servings from 1/2 can
1/24= (1/2)/x
cross multiply
1 * x= 24 * 1/2
x= 24/2
x= 12 servings
ANSWER: She can make 12 servings from 1/2 can of juice.
Hope this helps! :)
Answer:
x = 13
y = 15
Step-by-step explanation:
ST = DT ( Reason : from given )
5x = 65
x = 65 / 5
x = 13
TY = TU ( Reason : from given )
3y + 5 = 50
3y = 50 - 5
3y = 45
y = 45 / 3
y = 15
Answer:
Noooo
Step-by-step explanation: