If (20,8) and (25, 10) belong to a proportional relationship, what is the constant of proportionality

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

4 0

Answer:

The proportionality constant is 2/5

Step-by-step explanation:

Here, we want to get the proportionality constant

Let us view the two points as being points on a line

The constant of proportionality will be the slope of the line that connects the two points

Mathematically, we can use the formula for the slope of a line

We have this as;

m = (y2-y1)/(x2-x1)

(x1,y1) = (20,8)

(x2,y2)= (25,10)

m = (10-8)/(25-20) = 2/5

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Create a linear function f(x), whose graph has the given slope that meets the given condition. Slope of 7,f(7)=1. The equation o

kolbaska11 [484]

For a linear function, you want it in y= mx + b form
They give you the slope your x, and when they say f(7)=1 that's like saying when x=7, y=1, or the ordered pair (7,1). To make it in y=mx+b, you can plug these coordinates in to solve for b. So, 1=7(7)+b, after you plug in slope and your point. Do math, 1=49+b, b=-48
That's how I think it's done

8 0

3 years ago

Read number 5 and help me out plz add an explanation

maks197457 [2]

Answer:

the new values could be 3 and one half and 5 and one half.

Step-by-step explanation:

This is correct because they are asking for a new one. Also, one that has 3 as a difference in between.

PLEASE LOOK AT ATTACTHMENT!!!

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