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klemol [59]
3 years ago
13

Useable energy is lost each time energy is converted to another form of energy, true or false?

Mathematics
1 answer:
shepuryov [24]3 years ago
3 0

Answer:True,  becuase every time energy is converted to another form, is  some of it is bled off and it  made unusable.

Step-by-step explanation:

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Find the equation of the line that passes through the following lines points (0,-1) and (3,12).​
Temka [501]

Answer:

y=13/3x-1

Step-by-step explanation:

k=(y2-y1) /(x2-x1)

A(0,-1) x1=0,y1=-1

B(3,12) x2=3, y2=12

k=(12-(-1))/(3-0)

k=(12+1)/3

k=13/3

y-y1=k(x-x1)

y-(-1)=13/3(x-0)

y+1=13/3*x

y=13/3*x-1

8 0
3 years ago
Please help me solve this​
Viktor [21]

You can factor the 32 out of the sum:

\displaystyle \sum_{m=1}^\infty 32 \cdot \left(\dfrac{1}{2}\right)^{m-1} = 32\sum_{m=1}^\infty \left(\dfrac{1}{2}\right)^{m-1}

We can also change the index as follows

\displaystyle 32\sum_{m=1}^\infty \left(\dfrac{1}{2}\right)^{m-1} = 32\sum_{m=0}^\infty \left(\dfrac{1}{2}\right)^{m}

Now, we have a theorem that states that the series

\displaystyle \sum_{m=1}^\infty a^m

converges if and only if |a|, and in this case we have

\displaystyle \sum_{m=1}^\infty a^m = \dfrac{1}{1-a}

This is your case, because you have

|a|=\dfrac{1}{2}

which implies that your series converges, and the value is

\displaystyle 32\sum_{m=0}^\infty \left(\dfrac{1}{2}\right)^{m} = 32 \cdot \dfrac{1}{1-\frac{1}{2}} = 32\cdot 2 = 64

3 0
3 years ago
In the following formula what does x(down)1 equal in terms of other variables.
icang [17]

Answer:

It’s b

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The product of x and 9 equals 45
adell [148]

Answer:

5

Step-by-step explanation:

because ?*9=45

45÷9=5

4 0
2 years ago
Read 2 more answers
Need help with these two, please thanks
Musya8 [376]

Answer:

the answer is 93.6

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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