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3 years ago

Useable energy is lost each time energy is converted to another form of energy, true or false?

1 answer:

3 0

Answer:True, becuase every time energy is converted to another form, is some of it is bled off and it made unusable.

Step-by-step explanation:

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You have a six-sided die that you roll once. Let Ri denote the event that the roll is i. Let G j denote the event that the roll

Misha Larkins [42]

Answer:

a. $P (R3 | G1)=\frac{1}{5}$

b. $P (R6| G3)= \frac{1}{3}$

c. $P(G3|E)=\frac{2}{3}$

d. $P (E|G3)=\frac{2}{3}$

Step-by-step explanation:

The sample space associated with the random experiment of throwing a dice is is the equiprobable space {R1, R2, R3, R4, R5, R6}. Then,

a. The conditional probability that 3 is rolled given that the roll is greater than 1? $P (R3 | G1) = \frac{P (R3\bigcap G1)}{P(G1)} = \frac{1/6}{5/6} = \frac{1}{5}$

b. What is the conditional probability that 6 is rolled given that the roll is greater than 3? $P (R6| G3) = \frac{P (R6\bigcap G3)}{P(G3)} = \frac{1/6}{3/6} = \frac{1}{3}$

c. What is P [GIE], the conditional probability that the roll is greater than 3 given that the roll is even? $P(G3|E) = \frac{P (G3\bigcap E)}{P(E)} = \frac{2/6}{3/6} = \frac{2}{3}$

d. Given that the roll is greater than 3, what is the conditional probability that the roll is even? $P (E|G3) = \frac{P (E\bigcap G3)}{P(G3)} = \frac{2/6}{3/6} = \frac{2}{3}$

6 0

3 years ago

Open the picture and answer it pls

Nastasia [14]

Answer:

3.5

Step-by-step explanation:

11.5 - 2.5 = 9

9 - 5.5 = 3.5

and scalene triange means none of the 3 sides are equal...

3.5 does not equal 5.5 or 2.5

3 0

2 years ago

Read 2 more answers

Simplify the expression. Write the answer without using parentheses or negative exponents.

rodikova [14]

$\frac{ (x^4 y^2)^5 }{ (x^2 y)^2 } =\frac{ x^{4*5} y ^{2*5} }{ x ^{2*2} y ^2 } =\frac{ x^{20} y ^{10} }{ x^4y^2 } = x^{20-4} *y^{10-2}= x^{16} *y^{8}$

5 0

3 years ago

Select all the values that cannot be probabilities a. 3/5b. 1c. -0.45d. 0.06e. 1.16f. 0g. 5/3h. √2

nikitadnepr [17]

Answer:

c,-0.45 ,

e. 1.16

g. 5/3

h. √2

Cannot be probability.

Step-by-step explanation:

Probability of any occurrence is always in the interval of 0 to 1. 0 and 1 inclusive.

0≤P(A)≤1

Any value outside this boundaries cannot be probability.

Therefore, -0.45,1.16,5/3 and √2 cannot be probability.

4 0

3 years ago

Find the diameter of the object.<br><br> diameter: __ cm

Mashcka [7]

Answer: 1 1/5

Step-by-step explanation: 3/5 is the radius so you would times the radius by two to get the diameter which is 1 1/5.

4 0

2 years ago