Write each fraction as a decimal as a fraction and percent 53/53

A small radio transmitter broadcasts in a 69 mile radius. If you drive along a straight line from a city 93 miles north of the t

larisa86 [58]

Answer:

See Explanation

Step-by-step explanation:

According to the Question,

We have A small radio transmitter that broadcasts in a 69-mile radius. If you drive along a straight line from a city 93 miles north of the transmitter to a second city 78 miles east of the transmitter.

Thus,

The distance that you get reception is the length of the chord created by the intersection of the circle defining the edge of transmission and the line defining the car trip.

x2 + y2 = 69² this is the circle

And,

The Transmitter at the origin

City to the north at (0,93) & City to the east at (78,0)

the Slope is M=(-93/78)

Intercept is B= y - mx ⇒ 93 - (-93/78)(0) = 93

The equation of the line between the cities is y = (-93/78)x + 93

y = -93x/78 + 93 this is the line

Now, Solve the above two Equations

The intersection is gotten from the picture or solving:

x^2 + [(-93/78)*x + 93]^2 = 69^2

on solving we get, the points approximately are: (67.952,11.98 ) and (23.6277, 64.82)

Now,

From the Pythagorean theorem the total distance of the trip is:

d1 = √(93^2 + 78^2) ≈ 121.37miles

And the distance when the signal is picked up is:

d2 =√ [(67.952-23.627)^2 + (64.82 - 11.98)^2] ≈ 68.96 miles

You will pick up a signal from the transmitter in (d2/d1)*100 = 56% of the drive.

3 0

2 years ago

Scale Factor<br><br> Smaller Figure:<br> Larger Figure:<br> Please please help, no links

slega [8]

Answer:

2/3

Step-by-step explanation:

you reduce the fraction to get the scale factor. so 8/12 reduces down to 2/3 which is the scale factor

6 0

2 years ago

What are the next three terms in the sequence 5, 14, 23, 32, ...?

Rashid [163]

41, 50, 59
all you have to do is subtract the first number from the second number which is 9. then you add 9 to the last number to get your answer

5 0

3 years ago

If b/a=c/b=d/c=2/3, find the value of a:b:c:d

leva [86]

Answer:

the ratio would be 6.75:4.5:3:2

Step-by-step explanation:

replace d and c with

d=2 and c=3

Then using proportion multiplication, you will find that b is 4.5

now replace all b with 4.5.

Then again using proportion multiplication, you will get a is 6.75.

Plug in a, b, c, d in the ratio and you get 6.75:4.5:3:2

5 0

2 years ago

A sample of 11001100 computer chips revealed that 62b% of the chips fail in the first 10001000 hours of their use. The company's

STALIN [3.7K]

Answer:

Rule

If;

P-value > significance level --- accept Null hypothesis

P-value < significance level --- reject Null hypothesis

Z score > Z(at 90% confidence interval) ---- reject Null hypothesis

Z score < Z(at 90% confidence interval) ------ accept Null hypothesis

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

z score = 1.35

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

Question; A sample of 1100 computer chips revealed that 62% of the chips fail in the first 1000 hours of their use. The company's promotional literature states that 60% of the chips fail in the first 1000 hours of their use. The quality control manager wants to test the claim that the actual percentage that fail is different from the stated percentage. Determine the decision rule for rejecting the null hypothesis, H0, at the 0.10 level.

Step-by-step explanation:

Given;

n=1100 represent the random sample taken

Null hypothesis: H0 = 0.60

Alternative hypothesis: Ha <> 0.62

Test statistic z score can be calculated with the formula below;

z = (p^−po)/√{po(1−po)/n}

Where,

z= Test statistics

n = Sample size = 1100

po = Null hypothesized value = 0.60

p^ = Observed proportion = 0.62

Substituting the values we have

z = (0.62-0.60)/√{0.60(1-0.60)/1100}

z = 1.354

z = 1.35

To determine the p value (test statistic) at 0.01 significance level, using a two tailed hypothesis.

P value = P(Z<-1.35) + P(Z>1.35) = 0.0885 + 0.0885= 0.177

Since z at 0.10 significance level is between -1.645 and +1.645 and the z score for the test (z = 1.35) falls with the region bounded by Z at 0.1 significance level. And also the two-tailed hypothesis P-value is 0.177 which is greater than 0.1. Then we can conclude that we don't have enough evidence to FAIL or reject the null hypothesis, and we can say that at 0.10 significance level the null hypothesis is valid.

3 0

3 years ago