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masya89 [10]
3 years ago
14

LaMont works for a company in downtown Chicago. The firm encourages employees to use public transportation (to save the environm

ent) by providing them with transit passes at a cost of $270 per month.
a. If LaMont receives one pass (worth $270) each month, how much of this benefit must he include in his gross income each year?

b. If the company provides each employee with $270 per month in parking benefits, how much of the parking benefit must LaMont include in his gross income each year?
Business
1 answer:
Digiron [165]3 years ago
3 0

Answer:

a) $180

b) $180

Explanation:

Employee Fringe Benefits is a form of payment by an employer other than money. The limit for employee fringe benefit is often decided by the IRS every year. The statutory limit for the year 2016 was $255, 2019 was $265 and the new statutory limit for the year 2020 is $270.

In the question provided, since the particular year was not stated, we will assume that the year is 2016 of which the limit for employee fringe benefit was $255.

a. The cost of transit pass qualifies as employee fringe benefit. Based on 2016 statutory limits, LaMont excludes $255.

Therefore his amount of transit pass benefit to be included in gross income

= ($270 - $255)×12

= $180

b. The cost of parking benefits qualifies as employee fringe benefit. Based on 2016 statutory limits, LaMont excludes $255.

Therefore his amount of parking benefit to be included in gross income

= ($270 - $255)×12

= $180

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Use the information presented in Southwestern Mutual Bank's balance sheet to answer the following questions. Bank's Balance Shee
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Answer:

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This would increase the loans account and the deposit account by $100 respectively.

Explanation:

a) Data and Calculations:

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Assets                                    Liabilities and Owners' Equity

Reserves             $150          Deposits                         $1,200

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Chambersburg Corp Between 2016 and 2017, Chambersburg sold some equipment that had an original cost of $57,500 . Which statement
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Answer:

<em>Detailed Question lifted from google: </em>

<em>Use the information presented below for Chambersburg Corp for 2017 and </em>

<em>2016 to answer the questions that follow. Chambersburg uses the straight-line depreciation method. 2017 2016 Property, plant, and equipment $ 250,000 $190,000 Accumulated depreciation 100,000 85,000 Depreciation expense 62,500 47,500 Net sales 1,000,000 900,000 Average Total assets 625,000 475,000 Refer to the information for</em>

<em>Chambersburg Corp Between 2016 and 2017, Chambersburg sold some equipment that had an original cost of $57,500 . Which statement is most likely true concerning transactions that must have occurred during the period? </em>

<em>a. Chambersburg also purchased additional equipment during the year. </em>

<em> b. The selling price of the equipment sold was reported with net sales. </em>

<em> c. The equipment that was sold had a book value of $12,500. </em>

<em> d. The equipment sold had not been reported with Chambersburg's property, plant and equipment.</em>

<em />

The only applicable answer based on the question is A, <em>Chambersburg also purchased additional equipment during the year. </em>

Explanation:

A. Between 2016 and 2017 <em>Property, plant, and equipment increased by $60,000 (which is $250,000 minus $190,000)</em>

<em />

B. Between 2016 and 2017 Depreciation expense on <em>Property, plant, and equipment increased by $15,000 (which is $62,500 minus $47,500)</em>

<em />

<em>Meaning attributable depreciation to the new addition to PPE of $60,000 is actually $15,000.</em>

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3 0
3 years ago
A manufacturer of handcrafted wine racks has determined that the cost to produce x units per month is given by upper c equals 0.
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Answer:

The cost per month is increasing at a rate $365.

Explanation:

Differentiation Formula

  • \frac{d}{dx}(x^n)= nx^{n-1}  
  • \frac{d}{dx}(a)=0             [ where a is a constant]
  • \frac{d}{dx}(ax^n)=a \frac{d}{dx}(x^n)= anx^{n-1}

Given that,

A manufacturer of handcrafted wine racks has determined that the cost to produce x units per month is given by

c=0.2x^2+10,000.

Again given that,

the rate of changing production is 13 unit per month

i.e \frac{dx}{dt}=13

To find the cost per month, we need to find out the value \frac{dc}{dt} when production is changing at the rate 13 units per month and the production is 70 units.

c=0.2x^2+10,000

Differentiating with respect to t

\frac{d}{dt}(c)=\frac{d}{dt}(0.2x^2)+\frac{d}{dx}(10,000)

\Rightarrow \frac{dc}{dt}=0.2\frac{d}{dt}(x^2)+\frac{d}{dx}(10,000)

\Rightarrow \frac{dc}{dt}=0.2\times 2x^{2-1}\frac{dx}{dt}+0

\Rightarrow \frac{dc}{dt}=0.4x\frac{dx}{dt}

Plugging \frac{dx}{dt}=13

\Rightarrow \frac{dc}{dt}=0.4x\times 13

\Rightarrow \frac{dc}{dt}=5.2x

\frac{dc}{dt}|_{x=70}=5.2\times 70 [ plugging x=70]

            =364

[ The unit of c is not given. Assume that the unit of c is dollar.]

The cost per month is increasing at a rate $365.

4 0
2 years ago
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