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monitta
3 years ago
5

This box has the same length, width, and height as the two tennis balls. Which expression gives the volume of the empty space en

circling the tennis balls inside the box?
Mathematics
2 answers:
MArishka [77]3 years ago
6 0

Answer:

The answer is A

Step-by-step explanation:

I have already tried it and I got it correct not clikbait please trst

Nadusha1986 [10]3 years ago
4 0

Answer:

The upper left one

Step-by-step explanation:

That is option A

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Azlyn can ride her horse 15.2 miles per hour. She is in an endurance race that is 76 miles
Tema [17]

Step-by-step explanation:

Remember, math is a language

when you see per think fractions

15.2 miles per hour = 15.2 miles / 1 hour

since this is a fraction, Units can cancel just like numbers

To cancel miles and be left with hours rearrange the fraction

1 hour / 15.2 miles

then multiply by 72 miles

\frac{1hour}{15.2miles}  \times 72miles

the miles cancel and youre left with hours!

so youd write and solve 72 / 15.2

3 0
2 years ago
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cluponka [151]
C would be your answer

6 0
3 years ago
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What is the circumference of a ceiling fan
sattari [20]
Um I think that it is cucumber
3 0
3 years ago
A company has $54,000 in a bank account that pays an interest of 2% per year. How much money can I withdraw at the end of one ye
RSB [31]

Answer:

$55,080

Step-by-step explanation:

Hope this helps.

3 0
2 years ago
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Applying Properties of Exponents In Exercise,use the properties of exponents to simplify the expression.
Mkey [24]

Answer:

1.~e^{-2} \\2.~e^{\frac{7}{2}}\\3.~e^8\\4.~e^{\frac{-11}{2}}

Step-by-step explanation:

We have to simplify the given exponential exponents.

Exponential Properties:

e^0 =1\\e^a.e^b = e^{a+b}\\\\\displaystyle\frac{e^a}{e^b} = e^{a-b}\\\\(e^a)^b = e^{ab}\\\\e^{-a} = \frac{1}{e^a}

Simplification takes place in the following manner:

a)

(e^{-3})^\frac{2}{3}\\(e^a)^b = e^{ab}\\=e^{-3\times \frac{2}{3}}\\=e^{-2}

b)

(e^4)(e^{\frac{-1}{2}})\\e^a.e^b = e^{a+b}\\=e^{(4+\frac{-1}{2})} \\= e^{\frac{7}{2}}

c)

(e^{-2})^{-4}\\(e^a)^b = e^{ab}\\= e^{-2\times -4}\\=e^8

d)

(e^{-4})(e^{\frac{-3}{2}})\\e^a.e^b = e^{a+b}\\=e^{(-4+\frac{-3}{2})} \\= e^{\frac{-11}{2}}

4 0
3 years ago
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