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torisob [31]
3 years ago
9

Assuming that each of the 52 cards in an ordinary deck has a probability of 1/52 of being drawn, what is the probability of draw

ing a black ace?
Mathematics
1 answer:
Usimov [2.4K]3 years ago
8 0
\dfrac{2}{52}=\dfrac{1}{26}
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WILL MARK BRAINLIEST IF CORRECT!!! PLEASEE SOMEONE I HAVE 5 MINS
Dovator [93]

Answer:

a) 5+(-1)

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c) 4 is the value

4 0
2 years ago
The dimensions of a gymnastic floor are 40 ft by 40 ft. the performance floor is 1 ft less, or 39 ft, per side.
Mashutka [201]

Answer:

the square root of 3200

Step-by-step explanation:

I'm not sure if this is right, because the format of the question wasn't clear, but it sounded like we have to find the diagonal distance of the room from one corner to the opposite. If the sides are 40ft long on both sides, we can use the Pythagorean Theorem to solve this:

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2 years ago
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vladimir2022 [97]
The question is there
6 0
2 years ago
The probability of drawing two aces from a standard deck is 0.0059. We know this probability, but we don't know if the first car
ivanzaharov [21]

Answer:

Option C is right

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Step-by-step explanation:

Given that the  probability of drawing two aces from a standard deck is 0.0059

If first card is drawn and replaced then this probability would change.  By making draws with replacement we make each event independent of the other

Drawing ace in I draw has probability equal to 4/52, when we replace the I card again drawing age has probability equal to same 4/52

So if the two draws are defined as event A and event B,  the events are  independent

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4 0
3 years ago
What do they represent?
andrey2020 [161]

Answer:

A

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-15y = -6x + 15

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Because the 2 equations are the same now, they are the same line.

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3 years ago
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