Answer:
936mm^2
Step-by-step explanation:
Surface area of cuboid 20 mm 8mm 11mm
Surface area of the cuboid=2(20×8+8×11+11×20)
=2(160+88+×220)
=2(468)
=936mm^2
So the answer is936mm^2
1/620 is the simplest form of 2/1240
all you had to do was simplify
2 divided by 2=1
1240 divided by 2=620 <span />
Answer:
ASA
Step-by-step explanation:
Given:
Two triangles ABC and EDC such that:
AB ⊥ BD and BD ⊥ DE
C is the midpoint of BD.
The two triangles are drawn below.
Since, AB ⊥ BD and BD ⊥ DE
Therefore, the two triangles are right angled triangle. The triangle ABC is right angled at vertex B. The triangle EDC is right angled at vertex D.
Since, point C is the midpoint of the line segment BD.
Therefore, C divides the line segment BD into two equal parts.
So, segment BC ≅ segment CD (Midpoint theorem)
Now, consider the triangles ABC and EDC.
Statements Reason
1. ∠ABC ≅ ∠CDE Right angles are congruent to each other
2. BC ≅ CD Midpoint theorem. C is midpoint of BD
3. ∠ACB ≅ ∠ECD Vertically opposite angles are congruent
Therefore, the two triangles are congruent by ASA postulate.
So, the second option is correct.
The slope is 1/2 because to find a slope on a graph you use Rise/Run. So in this case it rise 1 and goes over 2