Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.



Let us find z-score of data point 22.03.



Using probability formula
, we will get:

Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
Answer:
1. 3/2
Domain =
-3, -2, 1, 4
Range =
-4, -2, 0, 3, 5
no it is not a function
Step-by-step explanation:
Answer:4 days ago — Click here to get an answer to your question ✍️ If X = 18 units, Y = 24 units, and Z = 30 units, what is the sine of.
Step-by-step explanation: