the remains of an ancient ball court include a rectangular playing alley with a perimeter of about 64 M. the length of the alley

Question

3 years ago

11

is 2 times the width. find the length and the width of the playing alley

1 answer:

igor_vitrenko [27] · Answer 1 · 2022-03-18T15:50:58+03:00

Answer:

<h2>The length is 21.3 meters</h2><h2>The width is 10.6 meters</h2>

Step-by-step explanation:

This problem is on the mensuration of flat shapes, a rectangular shape

we are required to solve for the length and width of the rectangular ball court

we know that the perimeter is expressed as

$P= 2(L)+2(W)$

let the width be x

hence the length is 2x

Given data

perimeter = 64 meters

length l= 2x

width w= x

Substituting our data and solving for x we have

$64= 2(2x)+2(x)\\\\64= 4x+2x\\\\64= 6x$

Dividing both sides by 6 we have

$x=\frac{64}{6}\\\\ x= 10.66$

Hence the width is 10.66 meters

The length is 2x= 2(10.66)= 21.33 meters