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tensa zangetsu [6.8K]
3 years ago
11

the remains of an ancient ball court include a rectangular playing alley with a perimeter of about 64 M. the length of the alley

is 2 times the width. find the length and the width of the playing alley​
Mathematics
1 answer:
igor_vitrenko [27]3 years ago
6 0

Answer:

<h2>The length is 21.3 meters</h2><h2>The width is 10.6 meters</h2>

Step-by-step explanation:

This problem is on the mensuration of flat shapes, a rectangular shape

we are required to solve for the length and width of the rectangular ball court

we know that the perimeter is expressed as

P= 2(L)+2(W)

let the width be x

hence the length is 2x

Given data

perimeter = 64 meters

length l= 2x

width w= x

Substituting our data  and solving for x we have

64= 2(2x)+2(x)\\\\64= 4x+2x\\\\64= 6x

Dividing both sides by 6 we have

x=\frac{64}{6}\\\\ x= 10.66

Hence the width is 10.66 meters

The length is 2x= 2(10.66)= 21.33 meters

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Plz solve if you can. Show ur work. I will name Brainliest! (: I need help plzzzzzzzzzz, especially on the check your work part.
maksim [4K]

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Add(2x)

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<u>Check your work</u>

-(-10)+4=-2(-10) - 6

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14=20 - 6

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Correct :)

2) 4R - 4 = 3R + 10

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<u>Check your work</u>

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2(-1)-3=-1-4

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3 years ago
Find the area of a circle with a diameter of 16 inches. Use 3.14 for pi.
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Answer:

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Answer:

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Step-by-step explanation:

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The zeros can also be found by trial and error, trying the choices offered by the rational root theorem: ±1, ±2, ±3, ±6. It is easiest to try ±1. Doing so shows that -1 is a root, and the residual quadratic is ...

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