Use the equation of motion under gravity:-
s = 16t^2 where s is the distance and t = time
2063 = 16t^2
t^2 = 2063 / 16 = 128.94 s
t = sqrt 128.94 = 11. 4 seconds to the nearest tenth of a second
Pierre ran 19 and 13/20 miles.
Given:
marathon length : 26 2/10 miles
pierre's length ran : 3/4 of the way.
Multiply the fractions.
Convert the marathon length from a mixed fraction into a fraction.
26 2/10 = ((26*10)+2)/10 = (260+2)/10 = 262/10
262/10 * 3/4 = (262*3) / (10*4) = 786/40 = 19 26/40
19 26/40 simplified to 19 13/20 miles
26 ÷ 2 = 13
40 ÷ 2 = 20
The answer is 2 because you have to divide 10 by 5 and the answer is 2<span />
Answer:
72 mles
Step-by-step explanation:
For better understanding, I'll make use of an attachment.
From the attachment,
O represents the start point
--- Jack
-- Distance between them
Required
Find OA; Jack's distance
To do this, we make use of Pythagoras theorem
This gives:
Subtract 900 from both sides
Take square roots
<em>Hence, Jill drove 72 miles</em>
