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2 years ago

If 15% of a number is 24 and 80% of the same number is 128, find 95% of that number.

Mathematics

1 answer:

IceJOKER [234]2 years ago

6 0

Answer:

It is 152

Step-by-step explanation:

I hope this helped

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What is15 qt/h= gal min

Brilliant_brown [7]

we have

$15 \frac{qt}{h}$

we know that

1 quarter is equal to 0.25 gallon

1 hour is equal to 60 minutes

convert $\frac{qt}{h}$ to $\frac{gal}{min}$

$15 \frac{qt}{h} =15* \frac{0.25}{60} = 0.0625\frac{gal}{min}$

therefore

the answer is

$0.0625\frac{gal}{min}$

5 0

3 years ago

Read 2 more answers

Sandra needs 6 pieces of rope, each measuring 8 inches in length. She is going to cut the 6 pieces from a rope that is 84 inches

soldier1979 [14.2K]

36 inches of rope will be left because 6*8 is 48 and you subtract 48 from 84 to get 36.

5 0

3 years ago

Grant attempted to solve an equation but made an error. What is his error, and

Vlad1618 [11]

Answer:

No Solution.

Step-by-step explanation:

-4+2x=5-(x-3)+3x

-4+2x=5-x+3+3x

-4+2x=5+3-x+3x

-4+2x=8+2x

-4+2x-2x=8

-4+0=8

-4=8

no solution

4 0

3 years ago

13) BRAINLIEST &10+ POINTS!

Sphinxa [80]

Answer:

- 220° and 500°

Step-by-step explanation:

To find the coterminal angles add / subtract 360°, that is

140° - 360° = - 220°

140° + 360° = 500°

7 0

3 years ago

A certain change in a process for manufacture of component parts is being considered. Samples are taken using both the existing

Katyanochek1 [597]

Answer:

a) The confidence interval is $0.00\leq\pi_1-\pi_2\leq0.02$ .

Step-by-step explanation:

We have to calculate a confidence interval (CI) of a difference of proportions.

For the existing procedure, the proportion is:

$p_1=75/1500=0.05$

For the new procedure, the proportion is:

$p_2=80/2000=0.04$

To calculate the CI, we need to estimate the standard deviation

$s=\sqrt{\frac{p_1(1-p_1)}{n_1} +\frac{p_2(1-p_2)}{n_2} }\\\\s=\sqrt{\frac{0.05(1-0.05)}{1500} +\frac{0.04(1-0.04)}{2000} }=\sqrt{ 0.000032 + 0.000019 }=\sqrt{ 0.000051 }\\\\s=0.007$

For a 90% CI, the z-value is 1.64.

Then, the CI is:

$(p_1-p_2)-z*\sigma \leq\pi_1-\pi_2\leq(p_1-p_2)+z*\sigma \\\\(0.05-0.04)-1.64*0.007\leq\pi_1-\pi_2\leq(0.05-0.04)+1.64*0.007\\\\0.01-0.01\leq\pi_1-\pi_2\leq0.01+0.01\\\\0.00\leq\pi_1-\pi_2\leq0.02$

6 0

3 years ago