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Lostsunrise [7]
3 years ago
15

The sides of a square field are 12 meters. A sprinkler in the center of the field sprays a circular area with a diameter that co

rresponds to a side of the field. How much is the field is not reached by the sprinkler? Round your answer to he nearest hundredth
Mathematics
1 answer:
loris [4]3 years ago
8 0
Area of the square is 144m.
Area of the circle is 113.1m.
Subtract A of circle from A of Square which equals 30.9meters. That is your answer.

If you want I can teach you step by step just comment if you want me to...
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A carpenter leans a 20-foot ladder against a building so that an angle of 60° is formed between the ladder and the ground. How m
iogann1982 [59]

Answer:

The foot of the ladder is

10

feet away from the base of the wall.

Step-by-step explanation:

8 0
3 years ago
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Please awnser this correctly! I will make you Brainliest!
Andrews [41]
Volume of cone: pi * r^2 * h/3
Given volume, height

942in^3 = 3.14 * r^2 * 9/3
942in^2 = r^2 * 9.42
Divide by 9.42
r^2 = 100, r = -10, 10
Cannot be negative so...

Solution: radius is 10 in.
8 0
2 years ago
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The Magazine Mass Marketing Company has received 10 entries in its latest sweepstakes. They know that the probability of receivi
Serjik [45]

Answer:

P(X>4)= 0.624

Step-by-step explanation:

Given that

n = 10

p= 0.5 ,q= 1 - p = 0.5

Two fifth of 10 = 2/5 x 10 =4

It means that we have to find probability P(X>4).

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

We know that

P(X=x)=(_{x}^{n})\ p^xq^{n-x}

P(X=0)=(_{0}^{10})\ 0.5^0\ 0.5^{10}=0.0009

P(X=1)=(_{1}^{10})\ 0.5^1\ 0.5^{9}=0.0097

P(X=2)=(_{2}^{10})\ 0.5^2\ 0.5^{8}=0.043

P(X=3)=(_{3}^{10})\ 0.5^3\ 0.5^{7}=0.117  

P(X=4)=(_{4}^{10})\ 0.5^3\ 0.5^{7}=0.205

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

P(X>4)= 1 -0.0009 - 0.0097 - 0.043 - 0.117-0.205

P(X>4)= 0.624

8 0
3 years ago
Read 2 more answers
Solve each system by substitution.<br> -<br> y = 6x – 11<br> -2x – 3y=-7
densk [106]

Answer:

Point form (2.1)

Equation form: x=2,y=1

5 0
3 years ago
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the weight M of an object on Mars varies directly as it’s weight E on Earth. A person who weighs 95 lb on Earth weighs 38 lb on
lorasvet [3.4K]

Answer:

A 100 lb person will weight 40 lb on Mars

Step-by-step explanation:

Given:

Weight on Mars directly varies as its weight on earth.

Let weight on Mars be = M

Let weight on Earth be = E

Its known that:

M ∝ E

Thus

M=kE

where k is constant of proportionality.

when  E=95\ lb, then M=38\ lb

thus, we have

38=k(95)

dividing both sides by 95.

\frac{38}{95}=\frac{k(95)}{95}

∴ k=\frac{38}{95}

Thus when E= 100, M would be calculated as

M=\frac{38}{95}\times 100

M=\frac{3800}{95}

∴ M=40\ lb  (Answer)

∴ A 100 lb person will weight 40 lb on Mars.

8 0
3 years ago
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