Answer:
yes I agree.both answer is same.I.e.15
Answer:
The system that represent the scenario is
The solution in the attached figure
Step-by-step explanation:
Let
x-----> the acres of corn
y----> the acres of cotton
we know that
------> inequality A
-----> inequality B
using a graphing tool
the solution is the shaded area in the attached figure
Answer:
I think it is C but not for sure
Step-by-step explanation:
Answer:
The slope is one.
Step-by-step explanation:
You can use the formula (y1-y2)/(x1-x2). Plugging in the points, it would be
(-1-1)/(-2-0) which simplifies to -2/-2, then just 1. You can also make a graph if you really aren't sure whether you did the problem right or make the full equation and plug the points in to make sure it checks out. :) Hope that helps?
The probability of selecting none of the correct six integers, when the order in which they are selected doesnot matter is 0.43.
According to thr question.
We have to find the probability of selecting none of the correct six integers from the positive integers not exceeding 48.
Let E be the event of selecting 6 numbers from 40 and S be the sample space of all integers not exceeding 48.
Now,
The total number of ways of selecting 6 numbers from 48
![= ^{48} C_{6}](https://tex.z-dn.net/?f=%3D%20%5E%7B48%7D%20C_%7B6%7D)
![= \frac{48!}{6!\times 42!}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B48%21%7D%7B6%21%5Ctimes%2042%21%7D)
![= \frac{48\times 47\times46\times45\times44\times43\times42!}{6!\times\ 42!}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B48%5Ctimes%2047%5Ctimes46%5Ctimes45%5Ctimes44%5Ctimes43%5Ctimes42%21%7D%7B6%21%5Ctimes%5C%2042%21%7D)
= 8835488640/6!
And, the total number of ways of selecting 6 incorrect numbers from 42
= ![^{42} C_{6}](https://tex.z-dn.net/?f=%5E%7B42%7D%20C_%7B6%7D)
![= \frac{42\times41\times40\times39\times38\times37\times36!}{6!\times36!}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B42%5Ctimes41%5Ctimes40%5Ctimes39%5Ctimes38%5Ctimes37%5Ctimes36%21%7D%7B6%21%5Ctimes36%21%7D)
= 3776965920/6!
Therefore, the probability of selecting none of the correct six integers, when the order in which they are selected does not matter is given by
![= \frac{^{42C_{6} } }{^{48} C_{6} }](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B%5E%7B42C_%7B6%7D%20%7D%20%7D%7B%5E%7B48%7D%20C_%7B6%7D%20%7D)
![= \frac{\frac{3776965920}{6!} }{\frac{8835488640}{6!} }](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B%5Cfrac%7B3776965920%7D%7B6%21%7D%20%7D%7B%5Cfrac%7B8835488640%7D%7B6%21%7D%20%7D)
= 3776965920/8835488640
= 0.427
≈ 0.43
Hence, the probability of selecting none of the correct six integers, when the order in which they are selected doesnot matter is 0.43.
Find out more information about probability here:
brainly.com/question/17083464
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