The number of combinations of 2 health care providers of different types possible are 47.
<u>Explanation:</u>
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Doctors = 4
Dentists = 3
Nurses = 5
combinations of two different health care providers = ?
Combination would be = ⁴C₁ X ³C₁ + ³C₁ X ⁵C₁ + ⁴C₁ X ⁵C₁
ⁿCₐ = n! / ( n - a )! X a!
So on calculating the combination we get,
= 4 X 3 + 3 X 5 + 4 X 5
= 12 + 15 + 20
= 47
Therefore, the number of combinations of 2 health care providers of different types possible are 47.
Answer:
I don't know what your asking here but if you could maybe be more specific, then maybe I could help.
Step-by-step explanation:
Needs more information.
Answer:
idk wii
Step-by-step explanation:
Answer:
(0,4)
Step-by-step explanation:
formula is y = mx + b
b is the y intercept
y intercept is where the line passes through the y axis
when x is 0 y is 14
because y = 6(0) + 14 -> y= 0+14 -> y= 14 when is 0
