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iogann1982 [59]
3 years ago
14

Which angles are coterminal with 7pi/8? Select each correct answer

Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0

Answer:

Step-by-step explanation:

-9pi/8

23pi/8

-25pi/8

I think its.

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4. Identify the height of the following triangle?<br> A.9<br> B. 5<br> C. 4<br> D. 12
OverLord2011 [107]

Answer:

if u look closely at the doted line it shows the height and the number on the inside right beside it is the height witch the answer would be C

5 0
3 years ago
What is the length of the line segment in the x-y plane with end points at (-2,-2) and (2,3)?
diamong [38]
(-2-2)^2+(-2-3)^2=16+25=41 Length is square root of 41
5 0
4 years ago
Is Q the midpoint of line segment PR? Justify your answer with numbers and words.
taurus [48]

Answer:

5x+8x+10-3=72\\13x=65\\x=5\\reapplying\\5(x+2)=5*7=35\neq (\frac{72}{2}=36 )

No it's not the Midpoint

3 0
3 years ago
Jessica is walking home from a friend's house. After two minutes she is 0.8 miles from home. Twelve minutes after leaving, she i
ycow [4]

Answer:

3 miles per hour

Step-by-step explanation:

Jessica is walking home from a friend's house.

After 2 minutes she is 0.8 miles from the home and after 12 minutes she is 0.3 miles away fro her house.

Her rate will be = (change in distance)/change in time

= (0.8-0.3)/(12-2)

= 0.5/10

= 0.05 miles per minute

Now we will convert timings from minutes to hour.

Or  = 0.05×60  

= 3 miles per hour

8 0
3 years ago
for a graph of a quadratic i have x intercepts that are x=12 and x =35 do i have enough information to find the y-coordinate of
goldenfox [79]

Answer:

No... provided no other information or no graph is provided.

Step-by-step explanation:

You can find the x-coordinate of the vertex which can be calculated using the two given x-intercepts. Using the symmetry of the parabola, it would just mean the vertex should lay midway between the x's. So the x-coordinate of the vertex is (12+35)/2=47/2.

However, we do not have enough information about the relationship between x and y to find the y-coordinate of the vertex.

All we are given is y=a(x-12)(x-35) (where a is real number) since we know the relationship is quadratic, and the zeros are 12 & 35.

So we could have many possible y-coordinates for our vertex since we don't know the value of a in our equation and we can plug in our x-coordinate for our vertex to find them all.

y=a(47/2-12)(47/2-35)

I'm just going to put everything to right of a in calculator:

y=-529/4 ×a

So that's all the possible y-coordinates for the vertex.

7 0
3 years ago
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