Which angles are coterminal with 7pi/8? Select each correct answer

If a bloodstain has a length of 3.0cm and a width of 1.5cm what is the angle of impact?

zalisa [80]

The angle of impact is 30°

<h3>What is the angle of impact?</h3>

In a bloodstain, the angle of impact can be used to determine the appearance of the resulting bloodstain if the bloodstain has a tail or pattern.

Bloodstain pattern analysis is the study of bloodstains at a scene of the crime in an attempt to reconstruct the events that resulted in the bloodshed.

Mathematically;

$\mathbf{Angle \ of \ impact = sin^{-1} (\dfrac{width \ stain}{length \ stain} )}$

$\mathbf{Angle \ of \ impact = sin^{-1} (\dfrac{1.5}{3.0} )}$

$\mathbf{Angle \ of \ impact = 30 ^0}$

Learn more about the angle of impact here:
brainly.com/question/19423063

6 0

2 years ago

Which linear equation could David use to determine y, the total distance he could swim without stopping to rest?

Gala2k [10]

Answer:

I would say C

Step-by-step explanation:

because I think that 15 is the slope and the 35 is the y intercept. I could be wrong but that would be my guess

8 0

3 years ago

Which equation shows 4n = 2(+ - 3) solved for T?

Ghella [55]

Answer:

C. T = 4n+6/2

Step-by-step explanation:

4n = 2(T-3)

or, 4n = 2T-6

or, 4n + 6 = 2T

or, 4n + 6 / 2 = T

or, T = 4n + 6 / 2

5 0

2 years ago

a school paid $31.50 for each calculator, if the school spent 504 dollars on calculators how many did the school buy?

monitta

The school bought 16 calculators.

504/31.50 =16

7 0

3 years ago

Two statistics teachers both believe that each has the smarter class. To put this to the test, they give the same final exam to

SVETLANKA909090 [29]

Answer:

We conclude that there is no difference between the two classes.

Step-by-step explanation:

We are given that two statistics teachers both believe that each has a smarter class.

A summary of the class sizes, class means, and standard deviations is given below:n1 = 47, x-bar1 = 84.4, s1 = 18n2 = 50, x-bar2 = 82.9, s2 = 17

Let $\mu_1$ = mean age of student cars.

$\mu_2$ = mean age of faculty cars.

So, Null Hypothesis, $H_0$ : $\mu_1=\mu_2$ {means that there is no difference in the two classes}

Alternate Hypothesis, $H_A$ : $\mu_1\neq \mu_2$ {means that there is a difference in the two classes}

The test statistics that will be used here is Two-sample t-test statistics because we don't know about the population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t_n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean age of student cars = 8 years

$\bar X_2$ = sample mean age of faculty cars = 5.3 years

$s_1$ = sample standard deviation of student cars = 3.6 years

$s_2$ = sample standard deviation of student cars = 3.7 years

$n_1$ = sample of student cars = 110

$n_2$ = sample of faculty cars = 75

Also, $s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(47-1)\times 18^{2}+(50-1)\times 17^{2} }{47+50-2} }$ = 17.491

So, the test statistics = $\frac{(84.4-82.9)-(0)}{17.491 \times \sqrt{\frac{1}{47}+\frac{1}{50} } }$ ~ $t_9_5$

= 0.422

The value of t-test statistics is 0.422.

Now, the P-value of the test statistics is given by;

P-value = P( $t_9_5$ > 0.422) = From the t table it is clear that the P-value will lie somewhere between 40% and 30%.

Since the P-value of our test statistics is way more than the level of significance of 0.04, so we have insufficient evidence to reject our null hypothesis as our test statistics will not fall in the rejection region.

Therefore, we conclude that there is no difference between the two classes.

6 0

3 years ago