Three lines given -- it's a natural for the cos(theta) law. A small hint: I think the preferred way of doing it is to use the cos(theta) law twice. It will give you a definite answer.
Find G first
g = 6 yd
h = 7 yd
f = 5 yards.
g^2 = h^2 + f^2 - 2*h*f*cos(G)
6^2 = 7^2 + 5^2- 2*7*5*cos(G)
36 = 49 + 25 - 70*Cos(G)
36 = 74 - 70*cos(G)
-48 = - 70 * cos(G) Divide by -70
-38/-70 = cos(G)
0.5429 = cos(G)
cos-1(0.5429) = G
G = 57.12
Now find H
h^2 = g^2 + f^2 - 2*g*f*cos(H)
7^2 = 5^2 + 6^2 - 2*5*6*cos(H)
49 = 25 + 36 - 60cos(H)
49 =61 - 60*cos(H)
Cos(H) = -12 / - 60
Cos(H) = 0.2
H = cos-1(0.2)
H = 78.46
F can be found because every triangle has 180 degrees
F + 78.46 + 57.12 = 180
F + 135.58 = 180
F = 180 - 135.58
F = 44.41
A <<<< Answer.
<span>The simplest method to do this is with the vector dot
product. Let the vector A = <9i + 5j> with magnitude √106 be the base
diagonal, and B = <5j + 3k> be the diagonal vector on the side, with
magnitude √34. Then cos θ = (A dot B) divided by the product of the magnitudes.
A dot B =30, so
cos θ = 30 / √(34 x 106)</span>
<span> = 0.4997 ==></span>
<span> θ = 49.19° is the
answer</span>
Hello,
adding 45 and 23, with these 2 datas, the range is already >=22.(45-23)
The new range cannot be 21
Answer A
Answer:
5
Step-by-step explanation:
