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prisoha [69]
3 years ago
11

To decide if 9cups are grater than 4 pints

Mathematics
2 answers:
Feliz [49]3 years ago
8 0
There are 2 cups in one pint. So, in 9 cups, there is 4.5 pints. So, 9 cups is greater than 4 pints
Naddika [18.5K]3 years ago
5 0
Yes 9 cups are greater than 4 pints. 2 cups equal 1 pint
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Step2247 [10]
I believe that the answer is b...the second one down.
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4 0
3 years ago
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Help me now plsss! can't think this one out.
ra1l [238]
She worked 30 hours per week.

The problem turns out to be the following:
2x+15=3x-15.
First you need to have only one x variable so you subtract the X's:
3x-2x=X
The problem now turns into 15=x-15.
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8 0
3 years ago
Suppose that x and y are both differentiable functions of t and are related by the given equation. Use implicit differentiation
stepan [7]

Answer:

Let z = f(x, y) where f(x, y) =0 then the implicit function is

\frac{dy}{dx} =\frac{-δ f/ δ x }{δ f/δ y }

Example:- \frac{dy}{dx}  = \frac{-(y+2x)}{(x+2y)}

Step-by-step explanation:

<u>Partial differentiation</u>:-

  • Let Z = f(x ,y) be a function of two variables x and y. Then

\lim_{x \to 0} \frac{f(x+dx,y)-f(x,y)}{dx}    Exists , is said to be partial derivative or Partial differentiational co-efficient of Z or f(x, y)with respective to x.

It is denoted by δ z / δ x or δ f / δ x

  • Let Z = f(x ,y) be a function of two variables x and y. Then

\lim_{x \to 0} \frac{f(x,y+dy)-f(x,y)}{dy}    Exists , is said to be partial derivative or Partial differentiational co-efficient of Z or f(x, y)with respective to y

It is denoted by δ z / δ y or δ f / δ y

<u>Implicit function</u>:-

Let z = f(x, y) where f(x, y) =0 then the implicit function is

\frac{dy}{dx} =\frac{-δ f/ δ x }{δ f/δ y }

The total differential co-efficient

d z = δ z/δ x +  \frac{dy}{dx} δ z/δ y

<u>Implicit differentiation process</u>

  • differentiate both sides of the equation with respective to 'x'
  • move all d y/dx terms to the left side, and all other terms to the right side
  • factor out d y / dx from the left side
  • Solve for d y/dx , by dividing

Example :  x^2 + x y +y^2 =1

solution:-

differentiate both sides of the equation with respective to 'x'

2x + x \frac{dy}{dx} + y (1) + 2y\frac{dy}{dx} = 0

move all d y/dx terms to the left side, and all other terms to the right side

x \frac{dy}{dx}  + 2y\frac{dy}{dx} =  - (y+2x)

Taking common d y/dx

\frac{dy}{dx} (x+2y) = -(y+2x)

\frac{dy}{dx}  = \frac{-(y+2x)}{(x+2y)}

7 0
3 years ago
List x1, x2, x3, x4 where xi is the midpoint endpoint of the five equal intervals used to estimate the area under the curve of f
Amanda [17]

Answer:

\bf x_1 = 2\\x_2 = 4\\x_3=6\\x_4=8

Step-by-step explanation:

The given interval : x = 0 to x = 10

Length of interval = 10 - 0

                              = 10

\text{Now, each }x_i \text{ is midpoint and endpoint of the five equal intervals}

⇒ Number of equal intervals = 5

\textbf{Length of each interval = }\frac{10}{5}

\textbf{Therefore, }\bf x_1 = 0 + 2 = 2\\x_2 = 2 +2 =4\\x_3=4+2=6\\x_4=6+2=8

3 0
3 years ago
Solve by sunstitution y=-x+4, y=3x
enyata [817]

Answer:

x=2

Step-by-step explanation:

y=-x+4   y=3x

3x=x+4

2x=4

x=2

(I hope this is the answer)

4 0
3 years ago
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