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wolverine [178]
3 years ago
5

How much warmer is itwhen the temperature is 17°F thanwhen it is -11°F?​

Mathematics
1 answer:
Rufina [12.5K]3 years ago
3 0

Answer:

i thinks it -11°F but not sure

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I have 2 questions to ask 1 is divide 180 degrees in a ratio of 4,5 and 9
MAXImum [283]

Here's how to do dividing in a certain ratio:

-- You want to divide up the whole thing in the ratio of
     4 parts, 5 parts, and 9 parts.

-- How many parts all together ?  (4 + 5 + 9) = 18 parts all together.

-- The whole thing is 180, and that's 18 total parts.
    So each part is  (180/18) = 10 degrees.

4 parts = (4 x 10) = 40
5 parts = (5 x 10) = 50
9 parts = (9 x 10) = 90.

Check:  (40 + 50 + 90) = 180 .                yay!

==============================

For the second one, I think there are some words missing.

5 0
3 years ago
Prove that the square of an odd number is always 1 more than a multiple of 4
loris [4]

Answer:

By these examples you are able to see that the square of an odd number is always 1 more than a multiple of 4.

Step-by-step explanation:

For examples,

Let's consider squares of 3, 11, 25, 37 and 131.

{3}^{2}  = 9

8 is a multiple of 4, and 9 is more than 8.

{11}^{2}  = 121

120 is a multiple of 4 and 121 is one more than it.

{25}^{2}  = 625

624 is a multiple of 4 and 625 is one more than it.

{37}^{2}  = 1369

1368 is a multiple of 4 and 1369 is one more than 1368.

{131}^{2}  = 17161

17160 is a multiple of 4.

5 0
2 years ago
Peter leaves Mitchell's house traveling 30 mph. Mitchell leaves 15 min later, trying to catch up to peter, going 40 mph. if they
UkoKoshka [18]

Answer:

  45 minutes

Step-by-step explanation:

At 30 mph for 1/4 hour, Peter has a 7.5 mile head start. After he leaves, Mitchell closes that gap at the rate of 40-30 = 10 miles per hour. It will take him ...

  t = d/s

  t = (7.5 mi)/(10 mi/h) = 0.75 h

to catch Peter.

Mitchell will catch Peter in 45 minutes.

__

<em>Alternate Solution</em>

Another way to look at it is that Mitchell's 10 mph advantage is 1/3 of Peter's speed, so it will take 1/(1/3) = 3 times the period of Peter's head start:

  3 × 15 minutes = 45 minutes . . . for Mitchell to catch Peter

_____

You can write equations involving time and distance and see where the distances traveled become the same. You need to be careful choosing the time reference, since you're concerned with Mitchell's travel time. I personally prefer to work "head start" problems by considering the differences in time and speed, as above. This is where you end up using the equations approach, anyway.

4 0
3 years ago
Multiplied by 3/4 and then divided by 3/5 is the same as dividing by what?
netineya [11]

We have:  x ×  \frac{3}{4} ÷ \frac{3}{5} = x ×  \frac{3}{4}  ×  \frac{5}{3} =  x × \frac{5}{4} = x ÷ \frac{4}{5}

ANSWER:  E. 4/5

Ok done. Thank to me :>

6 0
2 years ago
What is the slope of the line?<br> У<br> 1<br> X Х
ankoles [38]

Answer:151500

Step-by-step explanation:the is the answer

6 0
3 years ago
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