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VLD [36.1K]
3 years ago
10

URGENT!!! for the given situation identify the independent and D pendant variable‘s and then find a reasonable domain and range

of values listed below will be for statements that relate to the given situation. She’s is the statement that would have to be FALSE given the situation and it’s parameters
Roger has $12 to spend. He wants to buy some apples that cost $.60 apiece.
here are the statements
1) The dependent variable is how many apples he will buy
2) The range will be 0 to 20 apples
3) The domain will be any amount of money less than $12
4) The independent variable is how much money he will spend
Mathematics
1 answer:
sashaice [31]3 years ago
5 0

Answer:

3

Step-by-step explanation:

in order to be correct, it would have to be "any amount of money less than <em>or equal to</em> $12" because if it were less then, that makes the maximum amount he can spend $11.99.

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2 2/3 of what number is 6 1/7
borishaifa [10]

2\frac{2}{3} of 2\frac{17}{56} is 6\frac{1}{7}

Solution:

Given 2\frac{2}{3} of what number is 6\frac{1}{7}.

Let us first convert the mixed fraction into improper fraction.

$2\frac{2}{3}=\frac{(2\times3)+2}{3}=\frac{8}{3}

$6\frac{1}{7}=\frac{(6\times7)+1}{3}=\frac{43}{3}

Now, let us take the unknown number be x.

$2\frac{2}{3}\times x=6\frac{1}{7}

$\frac{8}{3}\times x=\frac{43}{7}

Do the cross multiplication.

$ x=\frac{43}{7}\times\frac{3}{8}

$ x=\frac{43\times3}{7\times8}

$ x=\frac{129}{56}

Now, again change the improper fraction into mixed fraction.

$ x=2\frac{17}{56}

Hence 2\frac{2}{3} of 2\frac{17}{56} is 6\frac{1}{7}.

6 0
3 years ago
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