A tank holds 3000 gallons of water, which drains from the bottom of the tank in half an hour. The values in the table show the v
1 answer:
Answer:
The slope of the secant line PQ is the following for each point:
Q Slope (a)
(5, 2097) -131.7 gal/min
(10, 1308) -105.6 gal/min
(20, 303) -95.4 gal/min
(25, 87) -69.3 gal/min
(30, 0) -52 gal/min
Step-by-step explanation:
The slope can be easily obtained by using a linear approximation for the 2 points P and Q. In this case, with the slope a:
(1)
(2)
if equations 1 and 2 are subtracted:
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To solve this we are going to use the future value of annuity due formula: ![FV=(1+ \frac{r}{n} )*P[ \frac{(1+ \frac{r}{n})^{kt}-1 }{ \frac{r}{n} } ]](https://tex.z-dn.net/?f=FV%3D%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%20%29%2AP%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bkt%7D-1%20%7D%7B%20%5Cfrac%7Br%7D%7Bn%7D%20%7D%20%5D)
where
is the future value
is the periodic deposit
is the interest rate in decimal form
is the number of times the interest is compounded per year
is the number of deposits per year
We know for our problem that
and 
. To convert the interest rate to decimal form, we are going to divide the rate by 100%: 
. Since Ruben makes the deposits every 6 months, 
. The interest is compounded semiannually, so 2 times per year; therefore, .
Lets replace the values in our formula:
![FV=(1+ \frac{0.1}{2} )*420[ \frac{(1+ \frac{0.1}{2})^{(2)(15)}-1 }{ \frac{01}{2} } ]](https://tex.z-dn.net/?f=FV%3D%281%2B%20%5Cfrac%7B0.1%7D%7B2%7D%20%29%2A420%5B%20%5Cfrac%7B%281%2B%20%5Cfrac%7B0.1%7D%7B2%7D%29%5E%7B%282%29%2815%29%7D-1%20%7D%7B%20%5Cfrac%7B01%7D%7B2%7D%20%7D%20%5D)
We can conclude that the correct answer is <span>$29,299.53</span>
where
We know for our problem that
Lets replace the values in our formula:
We can conclude that the correct answer is <span>$29,299.53</span>