Question

PLEASEE HELPP!!!!

Answer 1

y = - $\frac{1}{4}$ x + $\frac{15}{2}$

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = 4x + 5 is in this form with slope m - 4

Given the slope of a line m, then the slope ($m_{2}$) of a line perpendicular to it is

$m_{2}$ = - (1 / m ) = - $\frac{1}{4}$

y = - $\frac{1}{4}$ x + c is the partial equation of the perpendicular line

to find c, substitute ( 2, 7 ) into the partial equation

7 = - $\frac{1}{2}$ + c ⇒ c = $\frac{15}{2}$

y = - $\frac{1}{4}$ x + $\frac{15}{2}$ ← equation of perp. line