Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Answer: The Expression is Equivalent, However, NOT completely factored.
Step-by-step explanation:
3x^2 - 12
Following:
3 ( x^2 - 4 )
Factor:
3x^2 - 12
Factor Out Common Term 3:
3 ( x^2 - 4 ) = 3 (x^2 - 4 )
Factor:
x^2 - 4
( x + 2 ) ( x - 2 )
Answer:
3 ( x + 2) ( x - 2)
Hence, The Expression is Equivalent, However, Wasn't Completely Factored.
Hope that helps!
You multiply straight across, and one number is a fraction and the other is not.
I=ptr
i=(3000)(1461)(3.5%)
i=153405
his cost will be $153 405 by 4 years
Answer:
<em>Your Interquartile range (IQR) would be 19.</em>
Step-by-step explanation:
-5, 1, 3, 7, 8, 10, 32, 36
Median: 7.5
Lower quartile: 2
Upper quartile: 21
Interquartile range: 21 - 2 = 19
