The mean age is 29. Without rounding, it would be 29.4285714286
.
A, because you if you try to divide 0 into 15 parts you get 0
Answer:
A sample size of 1031 is required.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is of:

37% of freshmen do not visit their counselors regularly.
This means that 
98% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
You would like to be 98% confident that your estimate is within 3.5% of the true population proportion. How large of a sample size is required?
A sample size of n is required.
n is found when M = 0.035. So






Rounding up:
A sample size of 1031 is required.
Answer:
f= m - 5.5
Step-by-step explanation:
According to the table m is 15.25, so you would subtract 5.5 and you get 9.75 = f