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Ipatiy [6.2K]
2 years ago
8

The probability that a vehicle will change lanes while making a turn is 55%. Suppose a random sample of 7 vehicles are observed

making turns at a busy intersection. (a) Find the probability that no more than 4 vehicles will change lanes while making the turn.
Mathematics
1 answer:
bulgar [2K]2 years ago
5 0

The probability that no more than 4 vehicles will change lanes is 50.71%.

Since the probability that a vehicle will change lanes while making a turn is 55%, supposing a random sample of 7 vehicles are observed making turns at a busy intersection, to find the probability that no more than 4 vehicles will change lanes while making the turn, the following calculation must be performed:

  • ((0.55 x 4) + (0.45 x 3)) / 7 = X
  • 0.5071 = X

Therefore, the probability that no more than 4 vehicles will change lanes is 50.71%.

Learn more about maths in brainly.com/question/25936991

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Patrick earns $40 per hour. He earned an extra $1000 for working on a special project. His pay check for the month was 7420. How
Likurg_2 [28]
Patrick worked 160.5 hours because you have to subtract 1000 from 7420 then divide that by 40 for your answer. Also, Patrick has a sweet job.
3 0
3 years ago
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NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z​
Roman55 [17]

Answer:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

Step-by-step explanation:

Given system of equations:

\begin{cases}y=x^2-9\\y=4x-4\end{cases}

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}

Factor the quadratic:

\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}

Apply the <u>zero-product property</u> and solve for x:

\implies x+1=0 \implies x=-1

\implies x-5=0 \implies x=5

Substitute the found values of x into the <u>second equation</u> and solve for y:

\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}

\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}

Therefore, the solutions are:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

6 0
1 year ago
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Solve the equation 4y – 3 = 1 for y.<br> A.-1<br> B.0<br> C.1<br> D.2
zimovet [89]

Answer:

c

Step-by-step explanation:

4 times 1 is 4 and 4-3 is 1

8 0
3 years ago
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In an ore, 9.8% of its total weight is metal. How many pounds of metal are in 1,950 lb of ore?
Fudgin [204]

Answer

Find out the  how many pounds of metal are in 1,950 lb of ore .

To proof

let us assume that the pounds of metal are in 1,950 lb of ore be x .

As given

In an ore, 9.8% of its total weight is metal.

ore weight = 1,950 lb

9.8% is written in the decimal form

= \frac{9.8}{100}

= 0.098

Than the equation becomes

x = 0.098 × 1950

x = 191.1 pounds

Therefore the 191.1 pounds of metal are in 1,950 lb of ore .

Hence proved



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Is 6 less than 6.00?
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No, they are the same value.
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