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Which stamens is true

lesya [120]

The answer is B,

Explanation: I did the math :)

7 0

3 years ago

If f(x) = x* and g(x) = 3+8x?, find g(f(x)).

zhuklara [117]

g(8x-3)=x

have a good day

6 0

3 years ago

Looking to recieve help on this practice question, thank you!

dimaraw [331]

In general, the standard form of an ellipse is

$\begin{gathered} \frac{(x-h){}^2}{a^2}+\frac{(y-k)^2}{b^2}=1 \\ a,b,h,k\rightarrow\text{ constants} \\ (h,k)\rightarrow\text{ center} \end{gathered}$

Thus, in our case, complete the squares for x and y, as shown below

$\begin{gathered} 3x^2-12x=3(x^2-4x) \\ and \\ x^2-4x+c^2=(x-c)^2 \end{gathered}$

Finding c,

$\begin{gathered} \Rightarrow x^2-4x+c^2=x^2-2cx+c^2 \\ \Rightarrow-4x=-2cx \\ \Rightarrow c=2 \\ \Rightarrow3x^2-12x+3*4=3(x^2-4x+4)=3(x-2)^2 \end{gathered}$

Therefore, after adding +12 to both sides of the initial equation, we get,

$\begin{gathered} 3x^2+5y^2-12x+30y+42+12=12 \\ \Rightarrow3(x-2)^2+5y^2+30y+42=12 \end{gathered}$

Similarly, completing the square for the variable y,

$\begin{gathered} 5y^2+30y=5(y^2+6y) \\ \Rightarrow y^2+6y+c^2=(y-c)^2 \\ \Rightarrow y^2+6y+c^2=y^2-2cy+c^2 \\ \Rightarrow6=-2c \\ \Rightarrow c=-3 \end{gathered}$

Thus,

$\begin{gathered} \Rightarrow5y^2+30y+5*(-3)^2=5(y+3)^2 \\ \Rightarrow5y^2+30y+45=5(y+3)^2 \end{gathered}$

Therefore, after adding +45 to the initial expression

$\begin{gathered} \Rightarrow3(x-2)^2+5y^2+30y+42+45=12+45 \\ \Rightarrow3(x-2)^2+5(y+3)^2+42=57 \end{gathered}$

Then,

$\begin{gathered} \Rightarrow3(x-2)^2+5(y+3)^2=15 \\ \Rightarrow\frac{3(x-2)^2}{15}+\frac{5(y+3)^2}{15}=1 \\ \Rightarrow\frac{(x-2)^2}{5}+\frac{(y+3)^2}{3}=1 \end{gathered}$ <h2>The answer is the expression immediately above this line.</h2>

The center of the ellipse, its minor axis, and major axis are

$\begin{gathered} center\rightarrow(h,k)=(2,-3) \\ semi-minor\text{ axis}\rightarrow\sqrt{3} \\ semi-major\text{ axis}\rightarrow\sqrt{5} \end{gathered}$

7 0

1 year ago

The probability that an American company will open a location in Shanghai, China is 0.7. The probability that it will open a loc

kodGreya [7K]

Answer:

Step-by-step explanation:

Given that the probability that an American company will open a location in Shanghai, China is 0.7.

The probability that it will open a location in Beijing, China is 0.4.

The probability that it will open a location in either Shanghai or Beijing or both is 0.8.

the probability that the company will open a location in:

(a) both Shanghai and Beijing :

$0.7+0.4-P(both)=0.8$

P(both) = 0.3

(using addition theory of probability for union of sets)

(b) neither Shanghai nor Beijing

= 1- P(AUB)

$=1-0.8 = 0.2$

(c) Beijing but not in Shanghai?

P(Beiging)_P(both) = $0.4-0.3=0.1$

(d) Shanghai given that it opens a location in Beijing

=P(Both)/P(Beijing) = $\frac{0.3}{0.4} =0.75$

4 0

3 years ago

F(n)=4n-3 find the 15th term of the sequence defined by the explicit rule

Naddika [18.5K]

Answer:

Step-by-step explanation:

hello,

we need to evaluate f(15) so

f(15)=4*15-3=60-3=57

Hope this helps

7 0

3 years ago