How do you write 9.11 x 10 4 in standard form?

Mathematics

1 answer:

vitfil [10]3 years ago

7 0

Answer:

9400.11

Step-by-step explanation:

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Question 1

allochka39001 [22]

Answer:

Step-by-step explanation:

Perimeter of quarter circle = r + r + $\frac{1}{4}*2*\pi *r$

$= 10 + 10 + \frac{1}{4}*2*3.14*10\\\\= 10 + 10 + 3.14*5\\\\\\= 10 + 10 + 15.70\\\\= 35.70 cm$

2) d = 2*10 = 20 cm

Perimeter of semicircle = diameter + (1/2) * circumference of circle

$= 20 + \frac{1}{2}* 2*\pi *r\\\\= 20 + \frac{1}{2}*2*3.14*10\\\\= 20 + 3.14*10\\\\= 20 + 31.4\\\\= 51.40 cm$

3) Perimeter of three-quarter = r + r + (3/4)* circumference of circle

$= 10 + 10 + \frac{3}{4}*2*\pi *r\\\\= 10 + 10 + \frac{3}{4} * 2 * 3.14 * 10\\\\= 10 + 10 + 3 * 3.14 * 5\\\\= 10 + 10 + 47.1\\\\= 67.1 cm$

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3 years ago

HELP ME ASAP PLEASE I'LL GIVE U BRAINIEST Recall your studies of geometry (or another math course) and algebra. Choose one that

guajiro [1.7K]

This is what I put in my response

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3 years ago

Complete the square to the problem X^2+6x-16=0

marishachu [46]

Answer:

Step-by-step explanation:

$(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\-------------------------------\\\\x^2+6x-16=0\qquad\text{add 16 to both sides}\\\\x^2+6x=16\\\\x^2+2(x)(3)=16\qquad\text{add}\ 3^2\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=16+3^2\\\\(x+3)^2=16+9\\\\(x+3)^2=25\Rightarrow x+3=\pm\sqrt{25}\\\\x+3=-5\ \vee\ x+3=5\qquad\text{subtract 3 from both sides}\\\\\boxed{x=-8\ \vee\ x=2}$