$\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(-10,\:2\right),\:\left(x_2,\:y_2\right)=\left(0,\:-7\right)\\\\=\left(\frac{0-10}{2},\:\frac{-7+2}{2}\right)\\\\= (\frac{-10}{2} , \frac{-5}{2})\\ \\=\left(-5,\:-\frac{5}{2}\right)$

7 0

3 years ago

Triangle angle sun theorem<br> what the value of y?<br> I will give brainlist

hichkok12 [17]

Answer:

y = 7°

Step-by-step explanation:

By interior angle sum theorem of a triangle.

$51 \degree + 87 \degree + 6y = 18 \degree \\ \\ \implies 138 \degree+ 6y = 18 0\degree \\ \\ \implies 6y = 180 \degree - 138 \degree \\ \implies 6y = 42 \degree \\ \\ \implies y = \frac{42 \degree}{6} \\ \\ \huge \red{\implies y =7 \degree} \\ \\$

3 0

2 years ago