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andrew11 [14]
4 years ago
12

One serving of a cereal is 3/4 cup. Each box cereal has about 9 cups of cereal an costs $3.80. Is the price per serving greater

than $0.50? Explain
Mathematics
1 answer:
Zanzabum4 years ago
8 0
I think it is greater
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Solve the system of equations : y = x/2 , y = -x - 3 . You can use any method you wish for solving systems of equations. Check y
lorasvet [3.4K]

Answer:

x=−2 and y=−1

Step-by-step explanation:

<u>Problem:</u>

Solve y=x2;y=−x−3

<u>Steps:</u>

I will solve your system by substitution.

y=1/2x;y=−x−3

Step: Solve y= 1/2x for y:

Step: Substitute 1/2 x for y in y=−x−3:

y=−x−3

1/2x= =−x−3

1/2x+x=−x−3+x(Add x to both sides)

3/2x = -3

3/2x/3/2 = -3/3/2 (Divide both sides by 3/2)

x=−2

Step: Substitute −2 for x in y=1/2x:

y=1/2x

y=1/2(-2)

y=−1(Simplify both sides of the equation)

<u>Answer:</u>

x=−2 and y=−1

5 0
2 years ago
Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r
Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=\$1000\\\sigma=\$370\\n=80

As <em>n</em> = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let \bar X represent the sample mean weekly salaries.

The distribution of \bar X is: \bar X\sim N(\$1000,\ \$41.37)

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, |\bar X-\mu|= 75.

Compute the probability as follows:

P(-75

                                     =P(-1.81

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0
3 years ago
Alexis and Tasha challenged each other to a
Anvisha [2.4K]

Answer:

45 WPM

Step-by-step explanation:

A = 1.2T

54 = 1.2T

T = 45

8 0
3 years ago
Read 2 more answers
If the timer was started at the begining if the race would it affect the median. Why, not?
Ilia_Sergeevich [38]
Yeah It Would

~Hope This Helps :)
Need More Help With Question Just Inbox Me 
Also Rate, Give Thanks, And Mark As Brainiliest. 
Thank You ;) 
7 0
3 years ago
How do u solve 94=y/4-18. What do get for y.
Alexus [3.1K]
94=y/4-18
first you would +18 on each side with a result of 112=y/4 then you would x4 on each side with an end result of 448=y

y=448
3 0
3 years ago
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