Answer:
b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.
Step-by-step explanation:
Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.9 hours.
(Right tailed test at 5% level)
Mean difference = 0.2
Std error = 
Z statistic = 1.0540
p value = 0.145941
since p >alpha we do not reject H0.
b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.
Answer:
Amount invested at 8% is $9000 and amount invested at 18% is $21000.
Step-by-step explanation:
Let amount invested at 8% be x.
Let amount invested at 18% be y.
We get the 1st equation as:
........(1)
We get the second equation as:
=> 
or getting rid of the decimal by multiplying by 100 on both sides.
........(2)
Multiplying (1) by 8 and subtracting from (2) we get
So, y = 21000
And 
So, x = 9000
Therefore, amount invested at 8% is $9000 and amount invested at 18% is $21000.
Answer:
2.5th percentile and the 97.5th percentile.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
So we obtain the 0.025*100 = 2.5th percentile and the (1-0.025)*100 = 97.5th percentile.
So the answer is:
2.5th percentile and the 97.5th percentile.
It is 2 because no variable
