Botanist is the type of scientist that studies materials found in plants
Answer: Option A) 25mL
Explanation:
Given that,
Original volume of gas (V1) = 75mL
Original temperature of gas (T1) = 450K
New volume V2 = ?
New temperature T2 = 150K
Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law
V1/T1 = V2/T2
75mL/450K = V2/150K
To get the value of T2, cross multiply
75mL x 150K = 450K x V2
11250mL•K = 450K•V2
Divide both sides by 450K
11250mL•K / 450K = 450K•V2/450K
25mL = V2
Thus, the new volume of the gas is 25mL
<span> 2 moles of N2O5 = 4 moles of NO2
2.4 mol N2O5/1 X 4 mol NO2/2 mol N2O5 (this way you can cross out the N2O5 mol and just be left with NO2 mol)
2.4 X 4 = 9.6
9.6/2 = 4.8
4.8 mol NO2 are formed</span>
Answer:
G... what class work grade this is???
Answer:
22.4 g
Explanation:
We know we will need a balanced equation with molar masses, so let’s gather all the information in one place.
M_r: 2.016
4H₂O + 2NH₃ ⟶ 2NO₂ + 7H₂; Δ<em>H</em> = 216 kJ/mol NH₃
1. Calculate the <em>moles of NH₃
</em>
216 kJ ≡ 1 mol NH₃
Moles NH₃ = 685 × 1/216
Moles NH₃ = 3.171 mol NH₃
2. Calculate the <em>moles of H₂</em>
The molar ratio is 7 mol H₂:2 mol NH₃
Moles of H₂ = 3.171 × 7/2
Moles of H₂ = 11.10 mol H₂
3. Calculate the <em>mass of H₂</em>
Mass of H₂ = 11.10 × 2.016
Mass of H₂ = 22.4 g