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o-na [289]
3 years ago
8

Which type of scientist would most likely investigate how to synthesis materials found in plants

Chemistry
2 answers:
REY [17]3 years ago
6 0
Botanist! They are responsible for studies on plants and their makeup and operation of photosynthesis!
denis23 [38]3 years ago
4 0
Botanist is the type of scientist that studies materials found in plants
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Perform the following operation and express the answer in scientific notation. 8.20x10^-2x2.50x10^6
lora16 [44]
Answer is 2.05 x 10^{5}
7 0
3 years ago
Octane (C8H18) is a component of gasoline. Complete combustion of octane yields H2O and CO2. Incomplete combustion produces H2O
mestny [16]

86.5\; \% of octane had been converted to carbon dioxide CO₂.

<h3>Explanation</h3>

Octane has a molar mass of

12.01 \times 8 + 1.008 \times 18 = 114.22 \; \text{g} \cdot \text{mol}^{-1}

1.000 gallon of this fuel would have a mass of 2.650 kilograms or 2.65 \times 10^{3} \; \text{g}, which corresponds to 2.65 \times 10^{3} / 114.22 = 23.2\; \text{mol} of octane.

Octane undergoes complete combustion to produce carbon dioxide and water by the following equation:

2\; \text{C}_8\text{H}_{18} + 25 \; \text{O}_2 \to 16 \; \text{CO}_2 + 18 \; \text{H}_2\text{O}

An incomplete combustion of octane that gives rise to carbon monoxide and water but no carbon dioxide would consume not as much oxygen:

2\; \text{C}_8\text{H}_{18} + 17 \; \text{O}_2 \to 16 \; \text{CO} + 18 \; \text{H}_2\text{O}

The mass of the product mixture is 11.53 - 2.65 = 8.88 \; \text{kg} heavier than that of the octane supplied. Thus 8.88 \; \text{kg} = 8.88 \times 10^{3} \; \text{g} of oxygen were consumed in the combustion. There are 277.5 \; \text{mol} of oxygen molecules in 8.88 \times 10^{3} \; \text{g} of oxygen.

Let the number of moles of octane that had undergone complete combustion as seen in the first equation be x (0 \le x \le 23.2). The number of moles of octane that had undergone incomplete combustion through the second equation would thus equal 23.2 - x.

25 moles of oxygen gas is consumed for every two moles of octane that had undergone complete combustion and 17 moles if the combustion is incomplete.

n(\text{O}_2, \; \text{Complete Combustion}) + n(\text{O}_2, \; \text{Incomplete Combustion} ) = n(\text{O}_2, \; \text{Consumed})\\

\frac{25}{2} \; x + \frac{17}{2} \; (23.2 - x) = 277.5\\4 \; x = 277.5 - \frac{17}{2} \times 23.2\\x = 20.1

Therefore 20.1 \; \text{mol} out of the 23.2 moles of octane had undergone complete combustion to produce carbon dioxide.

\%n(\text{Complete Combustion}) = 20.1 / 23.2 \times 100 \; \%= 86.5\; \%

7 0
3 years ago
What is an example of conduction
kicyunya [14]

Hello There!

Conduction is the transfer of heat from one particle of matter to another.

“I Have 3 Examples Of Convection Provided Below”

“A Pot Sitting On A Hot Burner”

“Picking Up A Hot Cup Of Coffee”

“Feet On Hot Sand”

5 0
4 years ago
How can you tell how many valence electrons an element has
Dimas [21]

Answer:

the number of valence electrons is equal to the atom's main group number

Explanation:

3 0
2 years ago
The molarity of a solution that contains 8.0 g of NaOH in a liter of solution is
Kay [80]

Answer:

0.2M NaOh

Explanation:

there are 0.2 mol of NaOH in 8.0 g. (8.0/40) =0.2. Molarity = mol/L = 0.2M.

8 0
2 years ago
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