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pickupchik [31]
3 years ago
13

HELP NOW!!

Chemistry
1 answer:
s2008m [1.1K]3 years ago
6 0

Given, mass of isotope 1 = 39.06 amu

% abundance of isotope 1 = 10.00%

mass of isotope 2 =  42.14 amu

% abundance of isotope 2 = 90.00%

Average atomic mass

= [ (mass of isotope 1  x % abundance of isotope 1 ) + (mass of isotope 2 x % abundance of isotope 2 ) ]/ 100

= [(39.06 x 10) + (42.14 x 90)]/100

= (390.6 + 3792.6) / 100

= 4183.2/100

= 41.8 (to the nearest tenth)

Therefore, the weighted atomic mass of element Q is 41.8 amu.

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V_{2} = \frac{T_{2}}{T_{1}}\cdot V_{1}

V_{2} = \frac{347.348\,K}{298\,K}\cdot (0.12\,m^{3})

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