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PtichkaEL [24]
3 years ago
15

In how many orders can four girls and four boys walk through a doorway single file if

Mathematics
1 answer:
RideAnS [48]3 years ago
7 0

Answer:

(a) 40,320

(b) 576

Step-by-step explanation:

(a) We are asked to find the number of orders in which four girls and four boys can walk through a doorway single file if  there are no restrictions.

Since there are 8 people in total, so they can walk in 8! ways.

8!=8\cdot7\cdot6\cdot5\cdot4\cdot 3 \cdot 2\cdot1=40,320

Therefore, four girls and four boys walk through a doorway single file in 40,320 ways.

(b) To find the number of ways in which four girls and four boys can walk through a doorway single file if  the girls walk through before the boys.

The total number of ways would be equal to product of 4 girls walking first and 4 boys walking after.

4 girls can walk first in 4! ways and boys can walk after in 4! ways as well.

4!\cdot 4!=4\cdot 3\cdot 2\cdot 1\cdot 4\cdot 3\cdot 2\cdot 1=576

Therefore, four girls and four boys can walk through a doorway single file if  the girls walk through before the boys, in 576 ways.

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ANSWER

y = 3x - 3

EXPLANATION

Let

y = mx + c

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We can choose any two ordered pairs to determine the equation of the relation.

(6,15) \: and \:  (8,21)

We find m using the formula;

m =  \frac{y_2-y_1}{x_2-x_1}

m =  \frac{21 - 15}{8 - 6}  =  \frac{6}{2}  = 3

The equation becomes

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This implies that,

15 = 3(6) + c

15= 18 + c

15 - 18= c

c =  -3

The equation of the relation is therefore,

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