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mamaluj [8]
3 years ago
9

Please help me !!! need help will mark brainly

Mathematics
1 answer:
Ronch [10]3 years ago
4 0

Answer:

1. is 3 2/3

2. is 3 1/4

3. is 2 1/4

Hope this helped! :)

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Match each equation with its solution.1.2.3.4.<br> a.<br> b.<br> c.<br> d.
cupoosta [38]
Well I think it's b that's what I tjink
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3 years ago
Read 2 more answers
Write the number 3,2 and 8 in a addition sentence. Show two more ways to find the sum
Kisachek [45]
1.(3 + 2) + 8

2.5 + 8
4 0
3 years ago
b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

7 0
3 years ago
A player shoots a basketball from a height of 6 feet. The equation, h = -16t^2 + 25t + 6, gives the height, h , of the basketbal
noname [10]

Answer:

\boxed {\boxed {\sf 7.5 \ feet}}

Step-by-step explanation:

We are given this function for the height (h) after t seconds:

h=-16t^2+25t+6

Seconds is t and we want to find the height after 1.5 seconds. Plug 1.5 in for t.

h= -16(1.5)^2+25(1.5)+6

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

Solve the exponent first.

  • (1.5)²= 1.5*1.5=2.25

h= -16(2.25)+25(1.5)+6

Multiply.

h= -36+25(1.5)+6

h= -36+37.5+6

Add.

h=1.5+6=7.5

This is already rounded to the nearest tenth, so it is the answer.

After 1.5 seconds, the basketball is at a height of 7.5 feet.

6 0
3 years ago
What is 32767/32768 as a reduced fraction?
Anit [1.1K]
32,767/32,768 is in lowest terms and can't be reduced.
8 0
3 years ago
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