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jek_recluse [69]
3 years ago
14

It takes 5 days to repair 1,250 meters of road. At this rate, how many days will it take to repair 8 kilometers of road?

Mathematics
2 answers:
dolphi86 [110]3 years ago
6 0

Answer :

no. of days used to repair 1250m of road = 5

no. of days used to repair 1m of road = 5/1250

no. of days used to repair 8000m of road (8*1000m ) = 5/1250*8000= 32 days

UkoKoshka [18]3 years ago
4 0
5 days. 1250 meters
x days 8km=8000 meters
X=5•8000/1250
X=40000/1250
X=32 days
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Answer:

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Step-by-step explanation:

Your probably confused on what a, b, and c means.

The problems are written like this.

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That formula finds the zeros.

For example 1:

x^2-8x+15=0\\ax^2-bx-c\\a=1\\b=-8\\c=15

Then use the formula

x=\frac{-b+-\sqrt{b^2-4ac} }{2a} \\\\x=\frac{-(-8)+-\sqrt{-8^2-4(1)(15)} }{2} \\x=\frac{8+-\sqrt{64-60} }{2} \\\\x=\frac{8+-2}{2}\\

If plus then 5, if minus then 3

CHECK:

x^2-8x+15=0\\5^2-8(5)+15=0\\25-40+15=0\\0=0\\3^2-8(3)+15=0\\9-24+15=0\\0=0

Hope this helps you understand how to do this by yourself.  Now to do the rest ;-;

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