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3 years ago

It takes 5 days to repair 1,250 meters of road. At this rate, how many days will it take to repair 8 kilometers of road?

Mathematics

2 answers:

dolphi86 [110]3 years ago

6 0

Answer :

no. of days used to repair 1250m of road = 5

no. of days used to repair 1m of road = 5/1250

no. of days used to repair 8000m of road (8*1000m ) = 5/1250*8000= 32 days

UkoKoshka [18]3 years ago

4 0

5 days. 1250 meters
x days 8km=8000 meters
X=5•8000/1250
X=40000/1250
X=32 days

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1 year ago

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Option A

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3 years ago

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a_sh-v [17]

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cestrela7 [59]

Answer:

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Therefore :

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since it was given that y < 0 , then the factor will be $-\sqrt{10}y$

(b) $\sqrt{3y^{2}}$ can also be written as : $\sqrt{3}$ x $\sqrt{y^{2}}$

Therefore , one of the factor is $-\sqrt{3}y$

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3 years ago