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Alex787 [66]
3 years ago
10

Find the slope of the line that passes through the points (–1, 6) and (2, 15)

Mathematics
1 answer:
11111nata11111 [884]3 years ago
7 0

Answer:

m=3

Step-by-step explanation:

\frac{15-6}{2-(-1)} =\frac{9}{3} =3

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Solve for x
Liula [17]

Answer:

  x = {-4, 4}

Step-by-step explanation:

Subtracting 3 gives ...

  5x^2 = 80

Dividing by 5, we get ...

  x^2 = 16

Taking the square root gives the solutions ...

  x = ±4

The smaller value of x is -4; the larger value is 4.

4 0
3 years ago
Read 2 more answers
Jen spent $35 at the mall and now has $76 left. How much money did Jen have before she went shopping? Construct an equation to r
Levart [38]

Answer:

111

Step-by-step explanation:

x-35=76

x=111

4 0
3 years ago
Read 2 more answers
Write the equation of this circle in standard form.<br> please give answer?
Law Incorporation [45]

Given the center (x_0,y_0) and the radius r of a circle, its equation is

(x-x_0)^2+(y-y_0)^2=r^2

In your case, the center is (-4,0), and the radius is 2. Plug these values into the generic formula and you'll get the equation.

3 0
3 years ago
The table shows the values of a function f(x).
QveST [7]

Answer:

The average rate of change is =-4

Step-by-step explanation:

The average rate of change from x=a to x=b of f(x) is given by;

=\frac{f(b)-f(a)}{b-a}

We want to find the average rate of change of the function represented in the table  from x=-2 to x=2.

=\frac{f(2)-f(-2)}{2--2}

From the table f(-2)=25 and f(2)=9

The average rate of change from x=-2 to x=2 is

=\frac{9-25}{2--2}

=\frac{-16}{4}

=-4

3 0
3 years ago
Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equatio
Galina-37 [17]

Answer:

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

Step-by-step explanation:

Given:

Center of circle is at (5, -4).

A point on the circle is (x_1,y_1)=(-3, 2)

Equation of a circle with center (h,k) and radius 'r' is given as:

(x-h)^2+(y-k)^2=r^2

Here, (h,k)=(5,-4)

Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:

r^2=(h-x_1)^2+(k-y_1)^2

Using distance formula for the points (5, -4) and (-3, 2), we get

r^2=(5-(-3))^2+(-4-2)^2\\r^2=(5+3)^2+(-6)^2\\r^2=8^2+6^2\\r^2=64+36=100

Therefore, the equation of the circle is:

(x-5)^2+(y-(-4))^2=100\\(x-5)^2+(y+4)^2=100

Now, rewriting it in the form asked in the question, we get

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

4 0
3 years ago
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