Question

Graph the line with slope - 3/4 passing through point (4,-5)

Answer 1

Answer:

The graph in the attached figure

Step-by-step explanation:

we know that

The equation of the line in point slope form is equal to

$y-y1=m(x-x1)$

we have

$m=-\frac{3}{4}$

$point\ (4,-5)$

substitute

$y+5=-\frac{3}{4}(x-4)$

Convert to slope intercept form

$y=mx+b$

isolate the variable y

$y+5=-\frac{3}{4}x+3$

$y=-\frac{3}{4}x+3-5$

$y=-\frac{3}{4}x-2$

Find the intercepts

Find the y-intercept (value of y when the value of x is equal to zero)

For x=0

$y=-\frac{3}{4}(0)-2=-2$

The y-intercept is (0,-2)

Find the x-intercept (value of x when the value of y is equal to zero)

For y=0

$0=-\frac{3}{4}x-2$

$x=-\frac{8}{3}=-2.667$

The x-intercept is (-2.667,0)

To graph the line plot the intercepts and join the points

see the attached figure